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aev [14]
3 years ago
8

A particle moves along a straight line such that its position is defined by s = (t2 - 6t + 5) m. Determine the average velocity,

the average speed, and the acceleration of the particle when t = 6 s.
Engineering
1 answer:
Dominik [7]3 years ago
7 0

Answer:

0 m/s , 3 m/s , 2 m/s^2

Explanation:

Given : s(t) = ( t^2 - 6t + 5)

v(t) = ds / dt = 2t - 6

s(0) = 5 m

s(6) = (6)^2 - 6*6 + 5 = 5 m

Vavg = ( s(6) - s(0) ) / 2 = 0 m\s

Find the turning point of particle:

ds/dt = 0 = 2t - 6

t = 3 sec

s(3) = 3^2 -6*3 + 5 = - 4

Total distance = 5 - (-4) + (5 - (-4)) = 18 m

Total time = 6s

Average speed = Total distance / Total time = 18 / 6 = 3 m/s

Taking derivative of v(t) to obtain a(t)

a (t) = dv(t) / dt = 2 m/s^2

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A 1000-turn coil of wire 1.0 cm in diameter is in a magnetic field that increases from 0.10 T to 0.30 T in 10 ms. The axis of th
ddd [48]

emf generated by the coil is 1.57 V

Explanation:

Given details-

Number of turns of wire- 1000 turns

The diameter of the wire coil- 1 cm

Magnetic field (Initial)= 0.10 T

Magnetic Field (Final)=0.30 T

Time=10 ms

The orientation of the axis of the coil= parallel to the field.

We know that EMF of the coil is mathematically represented as –

E=N(ΔФ/Δt)

Where E= emf generated

ΔФ= change inmagnetic flux

Δt= change in time

N= no of turns*area of the coil

Substituting the values of the above variables

=1000*3.14*0.5*10-4

=.0785

E=0.0785(.2/10*10-3)

=1.57 V

Thus, the emf generated is 1.57 V

4 0
3 years ago
A hot brass plate is having its upper surface cooled by impinging jet of air at temperature of 15°C and convection heat transfer
gulaghasi [49]

Answer:

809.98°C

Explanation:

STEP ONE: The first step to take in order to solve this particular Question or problem is to find or determine the Biot value.

Biot value = (heat transfer coefficient × length) ÷ thermal conductivity.

Biot value = (220 × 0.1)÷ 110 = 0.2.

Biot value = 0.2.

STEP TWO: Determine the Fourier number. Since the Biot value is greater than 0.1. Tis can be done by making use of the formula below;

Fourier number = thermal diffusivity × time ÷ (length)^2.

Fourier number = (3 × 60 × 33.9 × 10^-6)/( 0.1)^2 = 0.6102.

STEP THREE: This is the last step for the question, here we will be calculating the temperature of the center plane of the brass plate after 3 minutes.

Thus, the temperature of the center plane of the brass plane after 3 minutes = (1.00705) (0.89199) (900- 15) + 15.

= > the temperature of the center plane of the brass plane after 3 minutes = 809.98°C.

5 0
3 years ago
Determine the nature of the following cycle (reversible, irreversible, or impossible): a refrigeration cycle draws heat from a c
vlabodo [156]

Answer:

Impossible.

Explanation:

The ideal Coefficient of Performance is:

COP_{i} = \frac{250\,K}{300\,K-250\,K}

COP_{i} = 5

The real Coefficient of Performance is:

COP_{r} = \frac{950\,kJ-70\,kJ}{70\,kJ}

COP_{r} = 12.571

Which leads to an absurds, since the real Coefficient of Performance must be equal to or lesser than ideal Coefficient of Performance. Then, the cycle is impossible, since it violates the Second Law of Thermodynamics.

6 0
3 years ago
What’s Statistics<br> What are the 2 Source of error in data collection
FromTheMoon [43]

Answer:

<em>The main sources of error in the collection of data are as follows : Due to direct personal interview. Due to indirect oral interviews. Information from correspondents may be misleading.</em>

4 0
3 years ago
Read 2 more answers
Which system of linear inequalities is represented by the graph? y &gt; x – 2 and y x + 1 y x + 1 y &gt; x – 2 and y &lt; x + 1
KatRina [158]

Answer:

The graph representing the linear inequalities is attached below.

Explanation:

The inequalities given are :

y>x-2   and y<x+1

For tables for values of x and y and get coordinates to plot for both equation.

In the first equation;

y>x-2

y=x-2

y-x = -2

The table will be :

x    y

-2  -4

-1    -3

0     -2

1      -1

2      0

The coordinates to plot are : (-2,-4) , (-1,-3), (0,-2), (1,-1) ,(2,0)

Use a dotted line and shade the part right hand side of the line.

Do the same for the second inequality equation and plot then shade the part satisfying the inequality.

The graph attached shows results.

5 0
3 years ago
Read 2 more answers
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