Answer:
A=1
B=-2
Explanation:
Part A and B of the question wasn't given, however, I attached the relevant parts to solve this question as follows.
From part B as attached, it shows that the right option is C which is
2A+3B=-4
Substituting B with 3A-5 then we form the second equation as shown
2A+3(3A-5)=-4
By simplifying the above equation, we obtain
2A+9A-15=-4
Re-arranging, then
11A=-4+15
Finally
11A=11
A=1
To obtain B, we already know that 3A-5 so substituting the value of A into the above then we obtain
B=3(1)-5=-2
Therefore, required values are 1 and -2
Answer:
1.73 m/s²
Explanation:
Given:
Δx = 250 m
v₀ = 0 m/s
t = 17 s
Find: a
Δx = v₀ t + ½ at²
250 m = (0 m/s) (17 s) + ½ a (17 s)²
a = 1.73 m/s²
Explanation:
1. Acceleration is the change in velocity over time.
a = Δv / Δt
a = (29.8 m/s − 37.1 m/s) / 3 s
a = -2.43 m/s²
2. Work equals force times distance.
W = Fd
W = (87.3 N) (2.04 m)
W = 178 J
3. Power is work per time.
P = W / t
267 W = 1250 J / t
t = 4.68 s
Answer:
The correct option is;
A. honk your horn if you cannot see at least 200 ft ahead
Explanation:
According the California Driver Handbook on Safe Driving Practices, it is required of the driver driving on a narrow mountain road without clear visualization of what is 200 ft ahead of her or him to honk the horn of the vehicle.
The sounding of the horn will alert those ahead of the driver of the possible danger due to her or his oncoming vehicle so that they (those ahead of the driver's oncoming vehicle) can react appropriately.
The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?
REFRACTIVE INDEX = 1.3
APPARENT DEPTH = 7.7 cm
REAL DEPTH OF THE OBJECT.
Refractive Index = 1.3
Apparent Depth = 7.7 cm
Putting the values in the formula:-
