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Musya8 [376]
3 years ago
13

Write a chemical equation for the reaction that occurs in the following cell: Cu|Cu2+(aq)||Ag+(aq)|Ag. Of the two metals, copper

and silver, which is the anode and which is the cathode? Label the oxidizing agent and the reducing agent.
Chemistry
1 answer:
KatRina [158]3 years ago
6 0

Answer:

Answer is given below.

Explanation:

Anode is that electrode where oxidation occurs. Cathode is that electrode where reduction occurs.

In cell representation, half cell present left to salt-bridge notation(\parallel ) is anodic system and another half cell present right to salt-bridge notation(\parallel ) is cathodic system.

So anode is Cu and cathode is Ag.

oxidation: Cu-2e^{-}\rightarrow Cu^{2+}(aq.)

[reduction: Ag^{+}+e^{-}\rightarrow Ag]\times 2

-----------------------------------------------------------------------------------------------

chemical equation: Cu+2Ag^{+}(aq.)\rightarrow Cu^{2+}(aq.)+2Ag

Oxidizing agent is that species which takes electron from another species. Here Ag^{+}(aq.) takes electron from Cu. Hence Ag^{+}(aq.)  is the oxidizing agent.

Reducing agent is that species which gives electron to another species. Here Cu gives electron to Ag^{+}(aq.) . Hence Cu  is the reducing agent.

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How long does it take electrons to get from the car battery to the starting motor? Assume the current is 137 A and the electrons
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Answer:

t = 55.79 min

Explanation:

First, the problem is asking for calculate the time that it takes electrons from the battery to the motor.

The general formula to calculate time is:

<em>t = d/V (1)</em>

Where:

d: distance or length

V: speed

Now, we don't have data of speed, but we can know an expression of current density in function of the distance which is the following:

<em>J = n*q*V (2)</em>

Where:

q: charge of the particle (1.6x10^-19 C)

n: number of charge carriers per unit of volume

Current density (J) is actually current per Area so:

<em>J = I/A (3)</em>

Replacing (3) in (2) we have:

I/A = nqV

Solving for V:

<em>V = I/Anq (4)</em>

Finally, if we replace this expression in (1) we have:

<em>t = nqAd / I (5)</em>

Now, the value of n, it's not given but it can be calculated because we have mass density, molar mass and avogadro's number, so this value of "n" can be calculated using the following expression:

<em>n = D * Av / MM (6)</em>

Where:

D: mass density (kg/m³)

Av: avogadro number (6.02x10^23 atom/mol)

MM: molar mass (kg/mol)

Putting the data that we know to calculate n we have:

n = 8960 * 6.02x10^23 / 0.0635

n = 8.49x10^28 atom/m³

Now with the value of n, we can finally calculate the time:

<em>t = nqAd / I </em>

A is the area and it should be in m²: 44.6 mm² / 1x10^6 m = 4.46x10^-5 m²

d is the length in meter: 75.7 cm / 100 cm/m = 0.757 m

so replacing these data in (5):

t = 8.49x10^28 * 1.6x10^-19 * 4.46x10^-5 * 0.757 / 137

t = 3,347.63 s

But the answer is in minute so:

t = 3,347.63 / 60

<em>t = 55.79 min</em>

so the electrons takes 56 min aprox. to go from the car battery to the starting motor.

4 0
3 years ago
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