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jenyasd209 [6]
2 years ago
13

Describe and explain the trend in atomic a.radius within the group.Explain the difference between the size of b.the atoms and th

e size of the ions.
Chemistry
1 answer:
disa [49]2 years ago
4 0

Answer:

A. The atomic radius increases (in a group) with the increasing atomic number. This is because atomic size generally increases from top to bottom within a group because the greater the number of protons means the greater amount of electrons. The amount of electrons in orbitals determine an atom's size/radius.

B. Since Group 1A (Alkali Metals) are metals, they tend to form cations. Cations are always smaller than their original atom because the greater positive charge from the nucleus closes in the space between it and the electrons, thus "shrinking" its size. This is why the ionic radii are smaller than the atomic radii of the same element.

I hoped this helped <3

Explanation:

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zlopas [31]

Answer: increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object.

Explanation:

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2 years ago
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The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?
anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

K_a\times K_b=K_w

K_b for sodium formate is K_b=\frac {K_w}{K_a}

Given that:

K_a of formic acid = 1.8\times 10^{-4}

And, K_w=10^{-14}

So,

K_b=\frac {10^{-14}}{1.8\times 10^{-4}}

K_b=5.5556\times 10^{-11}

Concentration = 0.35 M

HCOONa    ⇒     Na⁺ +    HCOO⁻

Consider the ICE take for the formate  ion as:

                                   HCOO⁻ + H₂O   ⇄   HCOOH + OH⁻

At t=0                              0.35                            -              -

At t =equilibrium           (0.35-x)                          x           x            

The expression for dissociation constant of sodium formate is:

K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}

5.5556\times 10^{-11}=\frac {x^2}{0.35-x}

Solving for x, we get:

x = 0.44×10⁻⁵  M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

<u>pH = 14 - 4.64 = 9.36</u>

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3 years ago
What is the molar mass of Ba3(PO4)2?
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Answer:

<h3>601.93 g/mol</h3>

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Problem: The Ba3(PO4)2 (molar mass = 601.93 g/mol) precipitate that formed from a salt mixture has a mass of 0.667 g.

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2 years ago
What are the different phases of matter and their characteristics?
Novay_Z [31]

Answer:

The five phases of matter. There are four natural states of matter: Solids, liquids, gases and plasma. The fifth state is the man-made Bose-Einstein condensates. In a solid, particles are packed tightly together so they don't move much.

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How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?
faltersainse [42]

Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

  • Volume of the solution (V): 500 mL
  • Molar concentration of the solution (M): 0.8 M = 0.8 mol/L

Step 2: Convert "V" to L

We will use the conversion factor 1 L = 1000 mL.

500 mL × 1 L/1000 mL = 0.500 L

Step 3: Calculate the moles of KBr (solute)

The molarity is the quotient between the moles of solute (n) and the liters of solution.

M = n/V

n = M × V

n = 0.8 mol/L × 0.500 L = 0.4 mol

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3 years ago
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