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3 years ago

Which of the following situations can be represented by the absolute value of 10? Check all that apply.

Mathematics

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer:

The situations that can be represented as an absolute value of 10 are:

Determine the size of Harold’s debt if he owes $10.
Determine how far −10 is from zero on a number line.
10 degrees is how many degrees above zero?

Step-by-step explanation:

Determine the size of Harold’s debt if he owes $10.

Even though he owes $10, which is reflected as -$10, the size of the debt is the absolute value ($10).

Determine how far −10 is from zero on a number line.

The distance is expressed in positive numbers, or using the absolute value.

10 degrees is how many degrees above zero?

The distance of the temperature is expressed in positive numbers, or using the absolute value.

Read more at below link:

brainly.com/question/16878090

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3 0

2 years ago

Factor completely and then place the factors in the proper location on the grid.

Pie

Answer is :
can find it on

5 0

2 years ago

Find the slope of the line that passes through the pair of points

love history [14]

Answer:

$\frac{5,805}{2812}$

Step-by-step explanation:

To find the slope from two points you can use the following formula:

$m = \frac{y -y_{1} }{x -x_{1} }$

Now substitute the two sets of points $(\frac{7}{20}, \frac{5}{19} ) and (\frac{5}{9}, \frac{11}{16})$

Substitute the values like this:

$y = \frac{5}{19}, y_{1} = \frac{11}{16}, x = \frac{7}{20}$ and $x_{1} =\frac{5}{9}$

Now you will need to simplify the following expression:

$m = \frac{\frac{5}{19} -\frac{11}{16} }{\frac{7}{20}-\frac{5}{9} }$

Make sure that denominators are the same before substracting:

$m = \frac{\frac{-129}{304} }{\frac{-37}{180} }$

when you divide with a fractional number you only need to flip the second fraction over (find its reciprocal). Then just multiply:

$m = (\frac{-129}{304} })({\frac{-180}{37} } ) = \frac{5805}{2812}$

5 0

3 years ago

Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y

koban [17]

$\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}$

Substituting this into the other ODE gives

$-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0$

Since $x(t)=-\dfrac14y'(t)$ , it follows that $x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16$ . The ODE in $y$ has characteristic equation

$r^2-16=0$

with roots $r=\pm4$ , admitting the characteristic solution

$y_c=C_1e^{4t}+C_2e^{-4t}$

From the initial conditions we get

$y(0)=5\implies 5=C_1+C_2$

$y'(0)=16\implies-16=4C_1-4C_2$

$\implies C_1=\dfrac12,C_2=\dfrac92$

So we have

$\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}$

Take the derivative and multiply it by -1/4 to get the solution for $x(t)$ :

$-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}$

7 0

3 years ago

Need help with my problem of the day it’s confusing I’m not good at math :| HELP

alex41 [277]

Answer:

7:36

Step-by-step explanation:

4 0

3 years ago