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2 years ago

Which of the following situations can be represented by the absolute value of 10? Check all that apply.

Mathematics

1 answer:

gtnhenbr [62]2 years ago

7 0

Answer:

The situations that can be represented as an absolute value of 10 are:

Determine the size of Harold’s debt if he owes $10.
Determine how far −10 is from zero on a number line.
10 degrees is how many degrees above zero?

Step-by-step explanation:

Determine the size of Harold’s debt if he owes $10.

Even though he owes $10, which is reflected as -$10, the size of the debt is the absolute value ($10).

Determine how far −10 is from zero on a number line.

The distance is expressed in positive numbers, or using the absolute value.

10 degrees is how many degrees above zero?

The distance of the temperature is expressed in positive numbers, or using the absolute value.

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kvasek [131]

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2 years ago

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Find the sum of the geometric sequence. 1, 1/2, 1/4, 1/8, 1/16

dezoksy [38]

I would convert them all to the denominator 16, due to the smallest fraction and all of them can be converted to it.

1 = 16/16
1/2 = 8/16
1/4 = 4/16
1/8 = 2/16
1/16 = 1/16

1+ 2 + 4 + 8 + 16 = 31

31/16 = 1 15/16

Hope this helps!

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3 years ago

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Write your answer for y.

Nonamiya [84]

Answer:

The coordinates of Y' will be: A'(4, -3)

Step-by-step explanation:

Triangle XYZ with vertices

X(-5, -2)

Y(-3, 4)

Z(-1, 1)

We have to determine the answer for the image Y' of the point Y(-3, 4) with respect to the line mirror y=x.

We know that when P(x, y) is reflected in y = x, we get P'(y, x)

i.e.

The rule of y=x:

P(x, y) → P'(y, x)

As we are given that Y(-3, 4), so the coordinates of Y' will be:

A(-3, 4) → A'(4, -3)

Therefore, the coordinates of Y' will be: A'(4, -3)

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2 years ago

6.1/5(12b+5) for b = 5/6

Temka [501]

Answer:

Step-by-step explanation:

6.1 / 5 ( 12b + 5 )

b = 5/6

by substituting,

6.1 / 5 ( 12 × 5/6 + 5 )

1.22 × 15

= <u><em>18.3</em></u>

Hope this helps

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2 years ago

Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined$

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3 years ago