Answer:
LOL
Explanation:
IMAGINE POSTING UR CLASSWORK LOLL
Answer:
Explanation:
Given:
angular speed of rotation of friction-less platform, 
moment of inertia with extended weight, 
moment of inertia with contracted weight, 
<u>Now we use the law of conservation of angular momentum:</u>
The angular speed becomes faster as the mass is contracted radially near to the axis of rotation.
Answer:
A(3.56m)
Explanation:
We have a conservation of energy problem here as well. Potential energy is being converted into linear kinetic energy and rotational kinetic energy.
We are given ω= 4.27rad/s, so v = ωr, which is 6.832 m/s. Place your coordinate system at top of the hill so E initial is 0.
Ef= Ug+Klin+Krot= -mgh+1/2mv^2+1/2Iω^2
Since it is a solid uniform disk I= 1/2MR^2, so Krot will be 1/4Mv^2(r^2ω^2= v^2).
Ef= -mgh+3/4mv^2
Since Ef=Ei=0
Mgh=3/4mv^2
gh=3/4v^2
h=0.75v^2/g
plug in givens to get h= 3.57m
if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.
<h3>What should you do if the rear end of the vehicle starts to slide or skid?</h3>
In the case above, a person need to Look as well as steer in the direction that the person want the front of the vehicle to go.
Note that in the case above;
Do stay way from the brake pedal and never apply the brakes.
- Steer in the the same direction as the rear of the vehicle that is known to be sliding. This will give room for the vehicle to go straight instead of going sideways.
- Then make sure to get ready to steer in the opposite direction if the vehicle is one that begins swerving in the other direction.
Therefore, if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.
Learn more about slide or skid from
brainly.com/question/2148046
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Answer:
a= kinetic energy vs. different masses at same speed, b= kinetic energy vs. same masses at different speeds
Explanation:
graphs are looking at speed so masses don't matter as much. same speed the whole time will equal same kinetic energy the whole time.
