Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Quadrant General Form of Point in this Quadrant Example
I (+, +) (5, 4)
II (−, +) (−5, 4)
III (−, −) (−5, −4)
IV (+, −) (5, −4)
<span>{[(16 ÷ 4) × (2 × 6)] ÷ 6} + 4 =
</span><span>{[(4) × (12)] ÷ 6} + 4 =
</span>{[4 × 12] ÷ 6} + 4 =
{[48] ÷ 6} + 4 =
{48 ÷ 6} + 4 =
{8} + 4 =
8 + 4 =
12
Answer:
B. 4
Step-by-step explanation:
Since d=√[7-3]2+[8-8]2
Answer:
15n
Step-by-step explanation:
Since it is 15 samples per day, you just need to multiple 15 by the number of days.
