During a storm, thunder is heared 7s after the lightining is seen. If the temperature of the air at the time of the storm is 28°
C .how far away is the storm?
2 answers:
Answer:
2 meters
Explanation:
time is directly proportional to temperarure where distance is the constant k
therefore
T = t x 2a
28=7 x 2a
28= 14a
a=2m
Answer:
2440 m
Explanation:
The speed of light in air is approximately 3×10⁸ m/s.
The speed of sound in air at 28°C is approximately:
v = 331.4 m/s + 0.6 m/s/°C (28°C)
v = 348.2 m/s
Let's say the distance between you and the storm is x.
Distance = speed × time
x = 3×10⁸ t₁
x = 348.2 t₂
Since t₂ = t₁ + 7:
x / 348.2 = x / 3×10⁸ + 7
Solving for x:
x (1/348.2 − 1/(3×10⁸)) = 7
x = 2440
The storm is approximately 2440 meters away (round as needed).
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Theories, brainliest pls???
newton's second law helps here.
mass times star velocuty minus mass times end velocity divided by time = force.
short time ,,, hig force
long time lower force ... padding reduces shock ... impulse
Answer:
s=vt2 just simplify all into metric units first
Momentum before = momentum after the push.
kinetic energy before < kinetic energy after the push.
Total displacement along the length of mountain is given as
L = 235 m
angle of mountain with horizontal = 35 degree
now we will have horizontal displacement as
x = L cos35
x = 235 cos35 = 192.5 m
similarly for vertical displacement we can say
y = L sin35
y = 235 sin35 = 134.8 m