Cl2(s); oxidation number 1 is the incorrect choices in oxidation number.
Explanation:
In the elemental form oxidation state is zero. Here chlorine is present in elemental form so oxidation state is zero.
Oxidation number depends on the number of electrons gained or lost by an atom of the element say in compound formation.
If electron is gained oxidation number becomes negative.
If electron is lost then oxidation number is positive.
If the octet rule is fulfilled that valence shell is filled them atomic number gets zero. Since Cl2 is in neutral state the oxidation number is 0.
Oxidation number in general can be made out by checking the valency of the element as oxidation number is also equal to the valency.
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Answer:</h3>
Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb
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Explanation:</h3>
We are required to write a balanced equation from the word equation;
- Nickel reacts with lead nitrate (II) to produce nickel(III) nitrate and lead
- The equation will be written by writing the symbols of the reactants and products.
That is;
Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb
We then balance the equation;
- To balance the equation, we put appropriate coefficients on reactants and products, so that the number of atoms of each element is equal on both sides of the equation.
- Thus, the balanced equation will be;
2Ni + 3Pb(NO₃)₂ → 2Ni(NO₃)₃ + 3Pb
A standardized test of what you want to do with your friends and you get to know what you think you want to be tre
<span>19.992*0.9048+20.993*0.0027+21.991+0.0925 = </span><span> 20.1797 amu (C)</span>
