<u>Answer</u>
5) b-c
6) a-b and
e-f
7) f-g
9) a-b = 0 m/s
c-d = 0.6667 m/s
e-f = 0 m/s
f-g = -3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
<u>Explanation</u>
Answer
5) b-c
In the section b-c the cart is accelerating because the slope of the graph is changing. The gradient that represent velocity is increasing.
6) a-b and e-f
At this sections the distance is not changing at all. This can only mean that the cart is not moving. It is at rest.
7) f-g
At this section the slope is negative meaning the cart is moving back to where it came from.
9) a-b = 0 m/s
At a-b the cart is not moving. So the velocity is zero.
<u> c-d = 0.66667 m/s</u>
Velocity = distance / time
=(50-40)/(40-25)
= 10/15
= 0.6667 m/s
<u> e-f = 0 m/s</u>
At e-f the cart is not moving. So the velocity is zero.
<u> f-g = -3 m/s</u>
Velocity = distance / time
= (60-30)/(65-75)
= 30/-10
= - 3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
Convection currents in the mantle.
Answer:
1 DC
2 DC
3 DC
4 AC
5 DC
Explanation:
AC means alternating current this type of current is not constant I.e time varying
This type of current is being supplied from power lines
DC means direct current and flows at a constant direction. This type of current is being supplied from batteries.
Answer:
r = 255.68 m
Explanation:
When a body moves in a circular path, an acceleration, due to constant change in its direction, is developed, known as centripetal acceleration. The centripetal acceleration acts towards the center of the circular path. The formula to calculate the centripetal acceleration is given as follows:
ac = v²/r
where,
ac = centripetal acceleration = 22 m/s²
v = tangential speed = 75 m/s
r = radius of curve = ?
Therefore,
22 m/s² = (75 m/s)²/r
r = (75 m/s)²/(22 m/s²)
<u>r = 255.68 m</u>
Answer:
A. 2.41 s.
B. 24.3 m/s.
Explanation:
vf = vi + 2a*t
where, vf = final velocity
= 0 m/s
vi = final velocity
= 1.5 m/s
a = 9.8 m/s^2
A.
ti = 1.5/(9.8 * 2)
= 0.08 s
Vf^2 = Vi^2 + 2a*s
1.5^2 = 2 * 9.8 * s
S = 0.115 m
Time taken to drop into the water,
30.115 = 1.5*to + 4.9*to^2
to = 2.33 s
Total time taken = ti + to
= 2.33 + 0.08
= 2.41 s.
B.
Vo = 0 m/s
S = 30.115 m
Vf = ?
Using,
Vf^2 = Vo^2 + 2*a*s
= sqrt (2*9.8*30.115)
= 24.3 m/s.
