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iris [78.8K]
4 years ago
10

A resistor, an inductor, and a switch are all connected in series to an ideal battery of constant terminal voltage. What does th

e time constant for the circuit represent? A resistor, an inductor, and a switch are all connected in series to an ideal battery of constant terminal voltage. What does the time constant for the circuit represent? The time constant represents the time required for the current to reach 25% of the maximum current. The time constant represents the time required for the current to reach 63% of the maximum current. The time constant represents the time required for the current to reach 99% of the maximum current. The time constant represents the time required for the current to reach 37% of the maximum current. The time constant represents the time required for the current to reach 75% of the maximum current. The time constant represents the time required for the current to reach 50% of the maximum current.
Physics
1 answer:
Irina-Kira [14]4 years ago
4 0

Answer:

The time constant τ = L/R represent the time requiered for the curent to get value of 63 % of its maximun value

Explanation:

In a circuit RL ( serie circuit with a resistor R and the inductor L ) when a voltage is applied the inductor will have a reaction, such reaction consist in the creation of an electromotive force which will prevent the current to get its maximun value. The time constant which in the case of an inductor is

τ = L/R ,  represent the time requiered for the crrent to be 63 % of its final value

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A loop circuit has a resistance of R1 and a current of 1.9 A. The current is reduced to 1.5 A when an additional 3.1 Ω resistor
Deffense [45]

Answer:

11.625 Ohm

Explanation:

Let V be the Voltage charge of the loop, as this is constant we know that before the resistor addition the current I is:

V/R1 = 1.9 or V = 1.9R1

After the resistor addition to series R = R1 + 3.1

I = V/R = V/(R1 + 3.1) = 1.5

We can substitute V = 1.9R1

1.9R1 = 1.5R1 + 1.5*3.1

0.4R1 = 4.65

R1 = 4.65/0.4 = 11.625 Ohm

4 0
4 years ago
The meeting in orbit of two or more spacecraft is A. orbital countermand. B. orbital farce. C. orbital hit. D. orbital rendezvou
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<span> D. orbital rendezvous</span>
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3 years ago
A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 4.79 g coins stacked over the 28.8 cm mark, th
masha68 [24]

To solve the exercise, the key concept to be addressed is the Mass Center.

The center of mass of an object is measured as,

X_{cm} = \frac{\sum m_ix_i}{\sum m_i}

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

Our values are given by,

x_1 = 50cm

m_1 = ?

x_2 =28.8cm

m_2 = 4.79g

x_3 = 28.8cm

m_3 = 4.79g

X_{cm} = 38.4cm

Replacing the values in our previous equation we have,

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

38.4 = \frac{m_1(50)+2(28.8*4.79)}{m_1+2*4.79}

38.4(m_1+2*4.79)= m_1(50)+2(28.8*4.79)

38.4m_1 +367.872 = 50m_1+275.904

11.6m_1 = 91.968

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7 0
3 years ago
Please answer this question given in the picture
elena-s [515]

A plane mirror forms a virtual image behind the mirror. The image is as far behind the mirror as the object is in front of it. A cannot see his image because the length of the mirror is too short on his side. However, he can see the objects placed at points P and Q, but cannot see the object placed at point R



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4 years ago
A 780g, 50-cm-long metal rod is free to rotate about a frictionless axle at one end. While at rest, the rod is given a short but
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Answer:

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