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agasfer [191]
3 years ago
12

The freezing temperatures for water for Celsius and Fahrenheit scales are 0ºC and 32ºF. The boiling temperatures for water are 1

00 ºC and 212 ºF. Let C denote the temperature in Celsius and F in Fahrenheit. Write the conversion function from Celsius to Fahrenheit. Use the function to convert 25 ºC into ºF.
Chemistry
1 answer:
ddd [48]3 years ago
7 0

Answer:

Therefore the required function is

C= \frac{5}{9} (F-32)

Therefore 25°C=57°F

Explanation:

F denotes temperature of Fahrenheit and C denotes temperature of Celsius.

\frac{C-0}{100-0} =\frac{F-32}{212-32}

\Rightarrow C= \frac{100}{180} (F-32)

\Rightarrow C= \frac{5}{9} (F-32)

Therefore the required function is

C= \frac{5}{9} (F-32)

Putting C=25°C in above equation

25=\frac{5}{9} (F-32)

\Rightarrow 25 \times \frac{9}{5} = F-32

⇒45 =F-32

⇒F=32+45

⇒F=57

Therefore 25°C=57°F

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Answer:

a. =9.1x10^3gC_3H_8

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a. By applying the given information, one obtains:

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b. By knowing that the propane has a molecular mass of 44g/mol, one obtains:

20lbC_3H_8*\frac{454gC_3H_8}{1lbC_3H_8}*\frac{1molC_3H_8}{44gC_3H_8} =2.1x10^2molC_3H_8

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One s orbital and three p orbitals combine to form four sp^{3} orbitals, each of which has a 25% s character and a 75% p character. This process is known as sp^{3} hybridization. Anytime an atom is surrounded by four groups of electrons, this kind of hybridization is necessary.

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