3. An object of mass 90 kg travels down a slide.

natali 33 [55]

The two letters are B and A, in that order.

7 0

3 years ago

At the accounting break-even point, Swiss Mountain Gear sells 22,940 ski masks at a price of $19 each. At this level of producti

gogolik [260]

Answer:

fixed cost $231220

Explanation:

given data:

quantity of skl mask = 22,940

skl mass rate = $19 each

variable cost = $6 per unit

therefore

Contribution/unit of ski mask = 19 - 6 = $13

for 22940 ski masks, total cost = (22940*13) = 298220

Depreciation cost $67000

fixed cost is = 298220 - 67000 = $231220

8 0

3 years ago

When two forces or more forces act on an object, the forces are

sashaice [31]

The forces are net forces. I think this is correct.

5 0

3 years ago

Four velcro-lined air-hockey disks collide with each other in a perfectly

Reil [10]

Answer:

The magnitude of the final velocity is approximately 0.526 m/s in approximately the direction of 8.746° East of South

Explanation:

The given collision parameters are;

The kind of collision experienced by the four velcro-lined air-hockey disk = Inelastic collision

The mass of the first disk, m₁ = 50.0 g

The velocity of the first disk, v₁ = 0.80 m/s West = -0.8·i

The mass of the second disk, m₂ = 60.0 g

The velocity of the second disk, v₂ = 2.50 m/s North = 2.5·j

The mass of the third disk, m₃ = 100.0 g

The velocity of the third disk, v₃ = 0.20 m/s East = 0.20·i

The mass of the fourth disk, m₄ = 40.0 g

The velocity of the fourth disk, v₄ = 0.50 m/s South = -0.50·j

Therefore, the total initial momentum of the four velcro-lined air-hockey disk, $\Sigma P_{initial}$ is given as follows;

$\Sigma P_{initial}$ = m₁·v₁ + m₂·v₂ + m₃·v₃ + m₄·v₄ = 50.0×(-0.80·i) + 60.0×(2.50·j) + 100 × (0.20·i) + 40.0 × (-0.50·j)

∴ $\Sigma P_{initial}$ = -40·i + 150·j + 20·i - 20·j = -20·i + 130·j

∴ $\Sigma P_{initial}$ = -20·i + 130·j

By the law of conservation of linear momentum, we have;

$\Sigma P_{initial} = \Sigma P _{final}$ = -20·i + 130·j

Therefore, given that the collision is perfectly inelastic, the disks move as one after the collision and the four masses are added to form one mass, "m", m = m₁ + m₂ + m₃ + m₄ = 50.0 + 60.0 + 100.0 + 40.0 = 250.0

∴ m = 250.0 g

Let, "v" represent the final velocity of the four disks moving as one after the collision

We have;

$\Sigma P _{final}$ = m × v = 250.0 × v = -20·i + 130·j

∴ v = -20·i/250 + 130·j/250 = -0.08·i + 0.52·j

The final velocity of the four disks after collision, v = -0.08·i + 0.52·j

The magnitude of the final velocity, $\left | v \right |$ = √((-0.08)² + (0.52)²) ≈ 0.526

$\left | v \right |$ ≈ 0.526 m/s

The direction of the final velocity, θ = arctan(0.52/(-0.08)) ≈ -81.254°

The direction of the final velocity, θ ≈ -81.254° which is 8.746° East of South

4 0

3 years ago

g Two balls of equal size are dropped from the same height from the roof of a building. The mass of ball A is twice that of ball

tamaranim1 [39]

Answer:

$K_A = 2K_B$

Explanation:

As we know that initial height of both the balls are same

also the mass of the two balls is given as

$m_A = 2m_B$

so here we can say by mechanical energy conservation

initial total mechanical energy = final total mechanical energy

since both balls are initially at rest so initial total kinetic energy of the balls will be zero

now final total kinetic energy = initial total potential energy

now we say

$K_A = m_A gh$

$K_B = m_B gh$

so we have

$\frac{K_A}{K_B} = \frac{m_A}{m_B}$

$K_A = 2K_B$

5 0

3 years ago