All categories

3 years ago

The process that enhances some properties of an object at the expense of other properties is called:

Physics

1 answer:

lidiya [134]3 years ago

6 0

Answer:

The answer is: letter a, pop-out effect.

Explanation:

The "pop-out effect" is a phenomenon which allows the person's precognitive processes to detect a<em> visual stimulus that is potentially the most meaningful one</em> in a person's spatial field of attention. The pop-up effect occurs when a person distinguishes one object from the rest.

For example, when a child chooses among pictures in different colors, it is common for the child to point at colored pictures rather than grayscale pictures. This is an example of a pop-out effect. <u>The properties of the colored pictures is more preferred by the child thus, causing him not to choose or mind the grayscale images.</u>

Thus, this explains the answer.

You might be interested in

¿que es la energia interna?

Vladimir [108]

Answer:

La energía interna es el resultado de la contribución de la energía cinética de las moléculas o átomos que lo constituyen, de sus energías de rotación, traslación y vibración, además de la energía potencial intermolecular debida a las fuerzas de tipo gravitatorio, electromagnético y nuclear.

Explanation:

4 0

4 years ago

Read 2 more answers

The model of the universe that suggests that the sun is the center of the universe was first brought by

gladu [14]

I think the correct answer from the choices listed above is option D. The model of the universe that suggests that the sun is the center of the universe was first brought by Copernicus. His model is known as the "Sun centered model".

5 0

3 years ago

Read 2 more answers

What would happen to the brightness of the bulbs if the switch was opened

jeka57 [31]

When the switch is open then no current can flow, on the other hand, when it is closed, current will pass through. When only “bulb a” is connected to the battery then more current is flowing to “bulb a” causing it to be bright. So the light of “bulb a” will be dimmer.

6 0

2 years ago

Consider the flow of an incompressible Newtonian fluid between two parallel plates that are 4 mm apart. If the upper plate moves

marin [14]

Answer:

Net flow rate = 0.00035 m³/s

Explanation:

The speed of plate 1, U₁ = 5 m/s

The speed of plate 2, U₂ = 1.5 m/s

The two plates are moving in different directions, the net speed will be gotten by taking the difference of the average of the two plates

The average speed due to the movement of plate 1 = U₁/2 = 5/2 = 2.5 m/s

The average speed due to the movement of plate 2 = U₂/2 = 1.5/2

= 0.75 m/s

The net average speed of the fluid= U₁/2 - U₂/2

The net average speed of the fluid = 2.5 - 0.75 = 1.75 m/s

Net flow rate = Net average speed * Area of the plate

Width of the plate, v = 5 cm = 0.05 m

Distance between the plates = 4 mm = 0.004 m

Area = 0.05 * 0.004

Area = 0.0002 m²

Net flow rate = 1.75 * 0.0002

Net flow rate = 0.00035 m³/s

8 0

3 years ago

A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward.

lord [1]

Correct question:

A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward. If the contact time with the sidewalk is 1/800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Answer in units of N.

Answer:

The magnitude of the average force exerted on the superball by the sidewalk is 592.8 N

Explanation:

Given;

mass of the superball, m = 57 g = 0.057 kg

initial velocity of the superball, u = 24 m/s

final velocity of the superball, v = 11 m/s

contact time with the sidewalk, t = 1 / 800 s

To determine the magnitude of the average force exerted on the superball by the sidewalk, we apply Newton's second law of motion;

F = ma

$But, a = \frac{v-u}{t} \\\\Thus, F = m(\frac{v-u}{t} )\\\\F = 0.057(\frac{11-24}{1/800} )\\\\F = 0.057(\frac{-13}{1/800})\\\\F = -0.057(\frac{800*13}{1})\\\\ F = -592.8 \ N\\\\Magnitude \ of \ the \ force \ is \ 592.8 \ N$

Therefore, the magnitude of the average force exerted on the superball by the sidewalk is 592.8 N

8 0

3 years ago