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deff fn [24]
3 years ago
13

Chemical reactions can be recognized by the presence of heat, light, or gas formation. The ultimate outcome for any chemical rea

ction is the... a) change from solid to a liquid b) presence of sound c) formation of a new chemical substance
Chemistry
1 answer:
Crank3 years ago
4 0

Answer:

c. formation of a new substance

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HBrO3 <br> A. All non metals “acid subcategory”
Irina-Kira [14]
Non metals acid subcategories
4 0
3 years ago
Choose the options below that are true.
Assoli18 [71]

Answer:

The options <u>(A) -</u>The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.  and <u>(C) </u>-The rate laws of bimolecular elementary reactions are second order overall ,<u>is true.</u>

Explanation:

(A) -The rate law can only be calculated from the reaction's slowest or rate-determining phase, according to the first sentence.

(B) -The second statement is not entirely right, since we cannot evaluate an accurate rate law by simply looking at the net equation. It must be decided by experimentation.

(C) -Since there are two reactants, the third statement is correct: most bimolecular reactions are second order overall.

(D)-The fourth argument is incorrect. We must track the rates of and elementary phase that is following the reaction in order to determine the rate.

<u>Therefore , the first and third statement is true.</u>

5 0
3 years ago
Which of these are physical changes in matter chech all that apply
serious [3.7K]

Answer:

a pencil being sharpened

freezing water

boiling water

Explanation:

a physical change doesn't change the chemical structure of an object. That is why the other 2 are wrong

6 0
3 years ago
Read 2 more answers
Nitrogen has an average atomic mass of 14.00674. it has two isotopes, n-14 and n-15, with atomic masses of 14.0031 amu and 15.00
masya89 [10]
In this case, we are going to assume that there are 100 atoms to make things easier. 

Let R% be the abundance of n-15. With this in mind, we calculate the abundance of n-14 to be 100%-R%

14.0031*(100-R)% + 15.001 * R%= 14.00674 
In this case, we can delete or ignore the % sign since we do not want to carry it around, however, we need to keep in mind that the final answer is in %

14.0031*(100-R) + 15.001 * R= 14.00674 
1400.31-14.0031R+15.001R=1400.674
0.9979R=0.364
R=0.3648

Then, the abundance of n-15 is 0.3648%

5 0
3 years ago
10. Which term is same for one mole of O2 and one mole of ethane C2H6
melamori03 [73]

Answer:

b) Number of molecules

Explanation:

3 0
3 years ago
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