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deff fn [24]
4 years ago
8

A sample of tap water contains 1.95 x 10^3 ppm caco3. assuming the density of the tap water is 1.00 g/ml, calculate the mass of

calcium carbonate in 2.0 l of water
Chemistry
1 answer:
Pavlova-9 [17]4 years ago
7 0
3.9 grams CaCO3  
The mass of 2.0 L of water with a density of 1.00 g/ml is 2000 grams.And 1 ppm of that is 2000 / 1000000 = 0.002 grams. So just multiply by the ppm of CaCO3, giving 0.002 g * 1.95x10^3 = 3.90 grams.  
Since the least accurate datum we have is 2 significant figures, the result should be rounded to 2 significant figures, giving 3.9 grams.
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How many molecules in 9.18 moles of C11H12O22
Setler [38]

Answer:

55.3 × 10²³ molecules

Explanation:

Given data:

Number of moles of C₁₁H₁₂O₂₂ = 9.18 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

For given data:

9.18 mol × 6.022 × 10²³ molecules /1 mol

55.3 × 10²³ molecules

5 0
3 years ago
The surface tension of which of the following liquid is maximum?
Elden [556K]
The cohesive forces between liquid molecules are responsible for the phenomenon known as surface tension<span>. I think the correct answer is option A. H2O will have the highest surface tension due to the hydrogen bonds that are present. Hope this answers the question. Have a nice day.</span>
8 0
3 years ago
Match the items
Nostrana [21]
1. D
2. F
3. A
4. E
5. B
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4 0
3 years ago
If a concentrated solution of acetic acid is 99.5 % HC2 H3 O2 and has a density of 1.05 g/mL, what is the concentration of this
cluponka [151]

Answer:

[CH₃COOH] = 17.4 M

Explanation:

Acetic acid → CH₃COOH

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99.5% is percent by mass concentration. It means that 99.5 grams of solute are contained in 100g of solution.

Density → 1.05 g/mL. This data is always referred to solution, not solute!.

We determine solution's volume:

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Now we know, that 99.5 g of acetic acid are contained in 95.2 mL

Let's convert to mmoles → 99.5 g / 60 g/mol = 1.66 moles

We convert solution's volume to L → 95.2 mL . 1L / 1000 mL = 0.0952 L

M (mol/L) = 1.66 mol / 0.0952 L = 17.4 M

5 0
4 years ago
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slavikrds [6]
The solubility of a sample will DECREASE when the size of the sample increases.
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5 0
3 years ago
Read 2 more answers
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