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deff fn [24]
3 years ago
8

A sample of tap water contains 1.95 x 10^3 ppm caco3. assuming the density of the tap water is 1.00 g/ml, calculate the mass of

calcium carbonate in 2.0 l of water
Chemistry
1 answer:
Pavlova-9 [17]3 years ago
7 0
3.9 grams CaCO3  
The mass of 2.0 L of water with a density of 1.00 g/ml is 2000 grams.And 1 ppm of that is 2000 / 1000000 = 0.002 grams. So just multiply by the ppm of CaCO3, giving 0.002 g * 1.95x10^3 = 3.90 grams.  
Since the least accurate datum we have is 2 significant figures, the result should be rounded to 2 significant figures, giving 3.9 grams.
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Mass of iron (III) oxide produced from oxygen=4 mol O_{2}*\frac{2 molFe_{2}O_{3}}{3 mol O_{2}}*\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} =  425.84 g Fe_{2}O_{3}

Iron (Fe) produces the least amount of the product iron (III) oxide. So, Fe is the limiting reactant.

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