Answer:
Now e is due to the ring at a
So
We say
1/4πEo(ea/ a²+a²)^3/2
= 1/4πEo ea/2√2a³
So here E is faced towards the ring
Next is E due to a point at the centre
So
E² = 1/4πEo ( e/a²)
Finally we get the total
Et= E²-E
= e/4πEo(2√2-1/2√2)
So the direction here is away from the ring
B, something with volume takes up space.
A)a gun moves backward while firing a bullet.
Explanation:
A gun moving backward while firing a bullet is a good example of newton's third law in action.
Newton's third law of motion states that "Action and reaction forces are equal and opposite in direction".
In shooting a gun, the bullet pulls forward by the action of the recoil down the barrel. This is the action force. The backward pull of the gun is the reactive force.
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Answer:
R = ½ R₀
Explanation:
This is an exercise in Ohm's law,
V = IR
in the initial case
V₀ = I₀ R₀ (1)
indicates that the voltage remains constant and the current is doubled
I = 2 I₀
V₀ = I R
we substitute
V₀ = 2 I₀ R
R = ½ V₀ / I₀
we replace by equation 1
R = ½ R₀
Answer:
d = 0.71 meters
Explanation:
It is given that,
Charge 1, 
Charge 2, 
Electrostatic force between charges, F = 9 N
Let d is the distance between the charges. The electrostatic force between the charges is given by the product of charges and divided by square of distance between them. Mathematically, it is given by :
d = 0.71 meters
So, the distance between the charges is 0.71 meters. Hence, this is the required solution.
