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The concentration of the final solution will be 0.2886 M.
<h3>Molar concentration</h3>
50.6 g of NaCl is dissolved in 600 mL of water.
Mole of 50.6 g NaCl = 50.6/58.44 = 0.8658 mol
Molar concentration of the oiriginal solution = 0.8658/06 = 1.4431 M
25 mL of 1.4431 M of the solution is diluted up to the 125 mL mark.
m1 = 1.4431, v1 = 25 ml, v2 = 125 mL
m2 = m1v1/v2 = 1.4431 x 25/125 = 0.2886 M
The concentration of the final solution will be 0.2886 M
More on molar concentration can be found here: brainly.com/question/15532279
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Answer:
Explanation:
remember that the phosphorous formula is P4
n P4 = mass / M.wt
825 / 4x 30.97 =
= 6.660 mole
Answer:
Sulphur (IV) Oxide solution
Explanation:
Sulphur (IV) Oxide with the chemical symbol 
is a covalent compound consisting only of nonmetals. In chemistry it is well known that Covalent compounds do not conduct electricity because they have no free electrons and ions.
