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3 years ago

What is C in the electronic circuit ??

Physics

1 answer:

shepuryov [24]3 years ago

6 0

Answer:

The Symbol is an n-p-n transistor

Explanation:

This is because the arrow on the transistor is pointing outside the transistor indicating that the current is flowing out from it

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Electric power is to be generated by installing a hydraulic turbine-generator at a site 120 m below the free surface of a large

iogann1982 [59]

Answer:

P = 2234400 Watt

Explanation:

Power generation is given as rate of work done

Here the turbine generator is located at 120 m below the free surface

So here rate of work done is given as rate of potential energy

$Power = \frac{dw}{dt}$

$Power = \frac{mgh}{t}$

so we have

$Power = (\frac{dm}{dt})gh$

now we have

$Power = 1900(9.8)(120) = 2234400 Watt$

so the power generation potential will be 2234400 Watt

8 0

3 years ago

A car traveling with constant speed travels 150 km in 7200 s. What is the speed of the car?

Wewaii [24]

75 km/h is the speed of the car

6 0

3 years ago

Read 2 more answers

A 74-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.56 m,

Reptile [31]

Answer:

Work done, W = 1.44 kJ

Explanation:

Given that,

Mass of boy, m = 74 kg

Initial speed of boy, u = 1.6 m/s

The boy then drops through a height of 1.56 m

Final speed of boy, v = 8.5 m/s

To find,

Non-conservative work was done on the boy.

Solution,

The work done by the non conservative forces is equal to the sum of total change in kinetic energy and total change in potential energy.

$W=\dfrac{1}{2}m(v^2-u^2)+(0-mgh)$

$W=\dfrac{1}{2}m(v^2-u^2)-mgh$

$W=\dfrac{1}{2}\times 74\times (8.5^2-1.6^2)-74\times 9.8\times 1.56$

W = 1447.21 Joules

W = 1.44 kJ

Therefore, the non conservative work done on the boy is 1.44 kJ.

4 0

3 years ago

What organ provides support for our

Marina86 [1]

Answer:

Skin

Explanation:

6 0

3 years ago

At 0.0 degrees Celsius, a wire cable is 410.0000 meters in length. When the temperature increased to 30.0 degrees Celsius, the w

zzz [600]

Answer: The coefficient of expansion for the wire $0.000028 (^oC)^{-1}$ .

Explanation:

Original length of the wire = L= 410.0000 m

Initial temperature = $T_1=0.0^oC$

Final Temperature = $T_2=30.0^oC$

Increase in Length of the wire = $\Delta L=0.3444 m$

$\frac{\Delta L}{L}=\alpha _{L}\times \Delta T=\alpha _{L}\times (T_2-T_1)$

$\alpha _L=\frac{\Delta L}{L\times (T_2-T_1)}=\frac{0.3444 m}{410.0000 m\times (30.0^oC-0.0^oC)}$

$\alpha _L=0.000028 (^oC)^{-1}$

The coefficient of expansion for the wire $0.000028 (^oC)^{-1}$ .

3 0

3 years ago