Given :
Two forces act on a 6.00-kg object. One of the forces is 10.0 N.
Acceleration of object 2 m/s².
To Find :
The greatest possible magnitude of the other force.\
Solution :
Let, other force is f.
So, net force, F = 10 + f.
Now, acceleration is given by :
Therefore, the greatest possible magnitude of the other force is 2 N.
Hence, this is the required solution.
Answer:
, charges are both positive or both negative
Explanation:
The electrostatic force between the two spheres is given by
where
k is the Coulomb's constant
q1 and q2 are the charges on the two spheres
r is the distance between the centres of the two spheres
In this problem, we have
is the force
is the distance between the spheres
because the two spheres have identical charge
Solving the formula for q, we find
And the two charges have the same sign (so, both positive or both negative), since the sign of the force is positive (+0.30 N), so it is a repulsive force.
Answer:
Explanation:
Given
two holes are made with different sizes
Hole 1 is large in size and hole 2 is small
If the volume flow rate of water is same for both the hole then small hole must be below the large hole because for same flow rate, velocity of water is large while cross-sectional area is small so it compensate to give same flow for both the holes.
Now for radius apply Bernoulli's theorem at hole 1 and 2
if hole 1 is h distance below water surface then
and
Also
and
thus