Answer:
0.53 N, 25.6°
Explanation:
side of triangle, a = 1.2 m
q = 7 μC
q1 = - 8 μC
q2 = - 6 μC
Let F1 be the force between q and q1
By using the coulomb's law


F1 = 0.35 N
Let F2 be the force between q and q2
By using the coulomb's law


F2 = 0.26 N
Write the forces in the vector form



Net force


Magnitude of the force

F = 0.53 N
Direction of force with x axis

θ = 25.6°
No. If time is the horizontal axis and distance is the vertical axis, then
it is not possible for a distance-vs-time graph to be a vertical line.
A vertical line would mean:
-- the object was at all distances at the same time,
-- it moved from any location to any other location in no time, and
-- it moved with infinite speed.
Even light doesn't do that. A distance-vs-time graph for light is
not a vertical line. It's a slanted line with slope of (3 x 10⁸) m/s.
Purty durn steep, but not vertical.
Pitch is related to frequency