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Veronika [31]
3 years ago
7

If a beam of light enters one medium from another medium, what quantity does not change?

Physics
1 answer:
wlad13 [49]3 years ago
4 0

The answer is D- Frequency

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In order to create an electromagnet, you would ?
Yakvenalex [24]
In order to create an electromagnet, you would wrap an insulated wire around a metal with ferromagnetic properties and apply electric current. Magnetic fields are made when entirely the electrons are turning in the same direction either as a natural phenomenon, in an artificially created magnet or when they are persuaded to do so by an electromagnetic field. 
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3 years ago
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a uniform disc and hollow right circular cone have the same formula for their moment of inertia when rotating about the central
Romashka-Z-Leto [24]

Answer:

This is as a result that about the central axis a collapsed hollow cone is equivalent to a uniform disc

Explanation:

The integration of the differential mass of the hollow right circular cone yields

I=\int\limits   dmr^2 = \int\limits^a_b {\frac{2Mxr^2}{R^2 +H^2} } \, dx  = \frac{2MR^2dx}{(R^2 +H^2)^2} \frac{(R^2 +H^2)^2}{4} = \frac{1}{2}MR^2

and for a uniform disc

I = 1/2πρtr⁴ = 1/2Mr².

6 0
3 years ago
Given the displacement vector D = (4î − 8ĵ) m, find the displacement vector R (in m) so that D + R = −3Dĵ. (Express your answer
Elena-2011 [213]

Answer:

--------------------------------

Explanation:

4 0
3 years ago
In a mass spectrometer a particle of mass m and charge q is accelerated through a potential difference V and allowed to enter a
Ghella [55]

Answer:

m = B²qR² / 2 V

Explanation:

If v be the velocity after acceleration under potential difference of V

kinetic energy  = loss of electric potential energy

1/2 m v² = Vq ,

v² = 2 Vq / m ----------------------- ( 1 )

In magnetic field , charged particle comes in circular motion in which magnetic force provides centripetal force

magnetic force = centripetal force

Bqv = mv² / R

v = BqR / m

v² = B²q²R² / m²  ------------------------- (2)

from (1) and (2)

B²q²R² / m²  = 2 Vq / m

m = B²q²R² / 2 Vq

m = B²qR² / 2 V

7 0
3 years ago
A force of 8.0 N is along x direction, another force of 6.0 N is along +y direction. If both forces are acting on a point object
Darya [45]

Answer:

Resultant force, R = 10 N

Explanation:

It is given that,

Force acting along +x direction, F_x=8\ N

Force acting along +y direction, F_y=6\ N

Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,

R=\sqrt{F_x^2+F_y^2+F_xF_y\ cos\theta}

Here \theta=90^{\circ}

R=\sqrt{F_x^2+F_y^2}

R=\sqrt{8^2+6^2}

R = 10 N

So, the resultant force on the object is 10 N. Hence, this is the required solution.

6 0
3 years ago
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