93.5 if it’s wrong sorry sis I need my homework done too
Your being on the moon has no effect on the moon's
gravitational field strength, or on the Earth's for that
matter.
However, YOU notice a change on YOU when YOU move
from one to the other, because of the effect of the gravitational
field strength on you and your internal organs.
If you could stand on the moon, you would experience an incredible
sense of lightness, since the forces of attraction between the moon
and anything else are only 16% as great as the same forces are on
Earth.
Answer:
Zero (0)
Explanation:
A horizontal line will be no movement of negative of positive acceleration
Answer: c) 90 m/s
Explanation:
Given
Invest velocity, v1 = 250 m/s
Inlet specific enthalpy, h1 = 270.11 kJ/kg = 270110 J/kg
Outlet specific enthalpy, h2 = 297.31 kJ/kg = 297310 J/kg
Outlet velocity, v2 = ?
0 = Q(cv) - W(cv) + m[(h1 - h2) + 1/2(v1² - v2²) + g(z1 - z2)]
0 = Q(cv) + m[(h1 - h2) + 1/2(v1² - v2²)]
0 = [(h1 - h2) + 1/2(v1² - v2²)]
Substituting the values of the above, we get
0 = [(270110 - 297310) + 1/2 ( 250² - v²)
0 = [-27200 + 1/2 (62500 - v²)]
27200 = 1/2 (62500 - v²)
54400 = 62500 - v²
v² = 62500 - 54400
v² = 8100
v = √8100
v = 90 m/s
Answer:
(a) 2.3 x 10^-12 N
(b) 1.6 x 10^5 m/s
Explanation:
q1 = 1.6 x 10^-19 C
q2 = 1.6 x 10^-19 C
r = 1 x 10^-8 m
(a) the electrostatic force is given by
F = K q1 x q2 / r^2
F = ( 9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (1 x 10-^-8)^2
F = 2.3 x 10^-12 N
The force is attractive in nature because the nature of charge on electron and proton s opposite to each other.
(b) The electrostatic force is balanced by the centripetal force actig on the electron.
F = mv^2 / r
where, r be the radius of orbit and v be the velocity of electron in the orbit.
2.3 x 10^-12 = (9.1 x 10^-31 x v^2) / (1 x 10^-8)
v = 1.6 x 10^5 m/s
