What number of moles of O2 is needed to produce 75 grams of P4010 from P?
1 answer:
Explanation:
We're using the chemical equation:
4P + 5O2 → P4O10
First convert grams of product to moles:
75g P4O10 x (1mol / 284 g) = 0.264 mol P4O10
Using the mole ratios, convert moles of product into moles of reactant needed:
0.264 mol P4O10 x (5 mol P / 1 mol P4O10) = 1.32 mol O2
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