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Tasya [4]
2 years ago
12

Explain why the amino group of p-aminobenzoic acid does not participate in the reaction

Chemistry
1 answer:
lubasha [3.4K]2 years ago
5 0

This is because amino group of p-aminobenzoic acid is an aniline and is less electrophilic than an alkyl amine.

<h3>What is an Aniline?</h3>

This is an aromatic amine which consists of a phenyl group attached to an amino group.

The amino group of p-aminobenzoic acid being an aniline makes it less electrophilic which is why an alkyl amine participates in the reaction instead.

Read more about Aniline here brainly.com/question/9982058

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NBr3—NCl3—NF3—CF4
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Balance the following equation <br>H2S+SO2➡️S+H2O
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What are the similarities between amorphous solid and crystalline solid <br><br>​
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3 years ago
A compound is made up of 28 g N, 24 g C, 48 g O, and 8 g H .What is the empirical formula?
vovikov84 [41]

Answer:

\rm C_2H_8N_2O_3.

Explanation:

<h3>Step One: calculate the coefficients. </h3>

Look up the relative atomic mass of these four elements on a modern periodic table:

  • \rm C: approximately 12.
  • \rm H: approximately 1.
  • \rm N: approximately 14.
  • \rm O: approximately 16.

The relative atomic mass of an element is numerically equal to the mass (in grams, \rm g,) of one mole of atoms of this element.

For example, the relative atomic mass of \rm C is approximately 12. Therefore, each mole of \rm C\! atoms would have a mass of 12\; \rm g.

This sample contains 24\; \rm g of carbon. That would correspond to approximately \displaystyle \left(\frac{24}{12}\right)\; \rm mol = 2\; \rm mol of \rm C atoms.

Similarly, for the other three elements:

\displaystyle n(\mathrm{H}) \approx \frac{8\; \rm g}{1\; \rm g \cdot mol^{-1}} = 8\; \rm mol.

\displaystyle n(\mathrm{N}) \approx \frac{28\; \rm g}{14\; \rm g \cdot mol^{-1}} = 2\; \rm mol.

\displaystyle n(\mathrm{O}) \approx \frac{48\; \rm g}{16\; \rm g \cdot mol^{-1}} = 3\; \rm mol.

Hence, the ratio between these elements in this compound would be:

n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3.

In the empirical formula of a compound, the coefficients should represent the smallest possible integer ratio between the number of atoms of these elements.

n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3 is indeed the smallest possible integer ratio between the number of atoms of these elements.

<h3>Step Two: arrange the elements in an appropriate order</h3>

Apply the Hill System to arrange these four elements in the empirical formula. In the Hill System:

If carbon, \rm C, is present in this compound, then:

  • \rm C (carbon) and then \rm H (hydrogen) will be the first two elements listed in the formula (ignore the hydrogen if it is not in the compound.)
  • The other elements in this compound will be listed in alphabetical order.

If there is no carbon \rm C in this compound, then list all the elements in this compound in alphabetical order.

Both \rm C (carbon) and \rm H (hydrogen) are found in this compound. Therefore, the first element in the list would be \rm C\!. The second would be \rm H\!, followed by \rm N\! and then \rm O\!.

Hence, the empirical formula of this compound would be \rm C_2H_8N_2O_3.

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