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aleksley [76]
3 years ago
8

A 1.0 × 10^3-kilogram car travels at a constant

Physics
1 answer:
laiz [17]3 years ago
6 0
Centripetal acceleration can be calculated with the formula F=v^2/r

Substituting the values in, we get:

a=20^2/50
=8

Therefore the magnitude of the centripetal acceleration of the car is 8 ms^-2
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Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart
Romashka [77]

Answer:

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

C = \frac{\epsilon  A}{d}

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A is area of square plate

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V = \frac{Q}{C}

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v = 9.523 V

Electric field is given as

E = \frac{V}{d}

   = \frac{9.52}{1.8*10^{-3}}

E   = 5291.00 V/m

E   = 5291.00 N/C

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