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Leya [2.2K]
3 years ago
7

For many years Colonel John P. Stapp, USAF, held the world's land speed record. He participated in studying whether a jet pilot

could survive emergency ejection. On March 19, 1954, he rode a rocket-propelled sled that moved down a track at a speed of 632 mi/h. He and the sled were safely brought to rest in 1.40s
(a) Determine the negative acceleration he experienced.
__ m/s2
(b) Determine the distance he traveled during this negative acceleration.
__ m.
Physics
1 answer:
Margarita [4]3 years ago
3 0

Answer:

(a) -202 m/s²

(b) 198 m

Explanation:

Given data

  • Initial speed (v₀): 283 m/s

\frac{632mi}{h} .\frac{1609.34m}{1mi} .\frac{1h}{3600s} =283m/s

  • Final speed (vf): 0 (rest)
  • Time (t): 1.40 s

(a) The acceleration (a) is the change in the speed over the time elapsed.

a = (vf - v₀)/t = (0 - 283 m/s)/ 1.40s = -202 m/s²

(b) We can find the distance traveled (d) using the following kinematic expression.

y = v₀ × t + 1/2 × a × t²

y = 283 m/s × 1.40 s + 1/2 × (-202 m/s²) × (1.40 s)²

y = 198 m

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Our data are,

State 1:

P_1= 10psi=68.95kPa\\V_1 = 1ft^3=0.02831m^3\\T_1 = 100\°F = 310.93K

State 2:

P_2 =5psi=34.474kPa\\V_2 = 3ft^3=0.0899m^3

We know as well that 3BTU=3.16kJ/K

To find the mass we apply the ideal gas formula, which is given by

P_1V_1=mRT_1

Re-arrange for m,

m= \frac{P_1V_1}{RT_1}\\m= \frac{68.95*0.02831}{(0.287)310.9}\\m=0.021893kg=0.04806lbm\\

Because of the pressure, temperature and volume ratio of state 1 and 2, we have to

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

Replacing,

T_2 = \frac{P_2V_2}{P_1V_1}T_1\\T_2 =\frac{34.474*0.0844}{68.95*0.02831}*310.93\\T_2 = 464.217K=375.5\°F

For conservative energy we have, (Cv = 0.718)

W = m C_v = 0.718  \Delta T +dw\\dw = W - mv\Delta T\\dw = 3.16-(0.0218*0.718)(454.127-310.93)\\dw = 0.765kJ=0.72BTU

3 0
3 years ago
Rubber is which of the following?
MariettaO [177]
Rubber is an insulator
8 0
3 years ago
describe why people are better off not consuming an additional good or service if the marginal cost is greater than the marginal
yulyashka [42]
I hosestly don’t know sorry need the points
3 0
3 years ago
A pizza delivery driver must make three stops on her route. She will first leave the restaurant and travel 4 km due north to the
topjm [15]
<h2>5.3 km</h2>

Explanation:

       This question involves continuous displacement in various directions. When it becomes difficult to imagine, vector analysis becomes handy.

       Let us denote each of the individual displacements by a vector. Consider the unit vectors \vec{i}\textrm{ and }\vec{j} as the unit vectors in the direction of East and North respectively.

       By simple calculations, we can derive the unit vectors \vec{j},\frac{-\vec{i}-\vec{j}}{2}\textrm{ and }\frac{-\frac{1}{2}\vec{i}+\frac{\sqrt{3}}{2}\vec{j}}{2} in the directions North, 45^{o} South of West and 60^{o} North of West respectively.

       So Total displacement vector = Sum of individual displacement vectors.

       Displacement vector = 4(\vec{j})+6(\frac{-\vec{i}-\vec{j}}{2})+5(\frac{-\frac{1}{2}\vec{i}+\frac{\sqrt{3}}{2}\vec{j}}{2})=-4.25\vec{i}+3.165\vec{j}

       Magnitude of Displacement = |-4.25\vec{i}+3.165\vec{j}|=5.3km

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4 0
3 years ago
In an experiment, a large number of electrons are fired at a sample of neutral hydrogen atoms and observations are made of how t
kakasveta [241]

Answer:

N = 1036 times

Explanation:

The radial probability density of the hydrogen ground state is given by:

p(r) = \frac{4r^{2} }{a_{0} ^{3} } e^{\frac{-2r}{a_{0} } }

p(\frac{a_{0} }{2} ) = \frac{4(\frac{a_{0} }{2} )^{2} }{a_{0} ^{3} } e^{\frac{-2(\frac{a_{0} }{2} )}{a_{0} } }

p(2a_{0} ) = \frac{4(2a_{0}) ^{2} }{a_{0} ^{3} } e^{\frac{-4a_{0} }{a_{0} } }

N = 1300\frac{p(2a_{0}) }{p(\frac{a_{0} }{2} )}

N = 1300\frac{(2a_{0}) ^{2}e^{\frac{-4a_{0} }{a_{0} } }  }{(\frac{a_{0} }{2} )^{2} e^{\frac{-a_{0} }{a_{0} } }}

N = 1300(16) e^{-3}

N = 1035.57

N = 1036 times

6 0
3 years ago
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