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Vedmedyk [2.9K]
3 years ago
14

According to Newton's 2nd law of motion, Jim can throw - with equal amounts of force applied - a _____ farther than a _____.

Physics
2 answers:
PtichkaEL [24]3 years ago
5 0

Answer:

all of the above

Explanation:

Remember that the second law of newton states that the acceleration of an object depends on two things, the net force applied to the object and the obeject´s mass, so if two objects are applied the same force, but have different mass their acceleration will be different, and since in all of the options the first object has less mass than the second, the first object will always travel farther than the second, making the option All of the above the correct one.

kodGreya [7K]3 years ago
3 0

The answer is All of the above

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3 years ago
At t=0, a block A of mass 8 kg and block B of mass 16 kg are both at position x=0 . Block A is at rest, and block B is moving at
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The center of mass of the two objects is the average position of the parts of the two object system

The center of mass of block <em>A</em>, and block <em>B</em>  after displacement of block <em>B</em> is at <u>20 m from block </u><u><em>A</em></u>

<em />

Reason:

The given parameters are;

The position of block A and block B at t = 0 is x = 0

The mass of block A, m₁ = 8 kg

Mass of block B, m₂ = 16 kg

Speed of block <em>A</em> = 0 m/s

Speed of block <em>B</em>, v₂ = 10 m/s

Location of the center of mass of the two object at t = 3 s; Required

Solution;

The location of block <em>A</em>, after 3 s is x₁ = 0 (block A is at rest)

The location of block <em>B</em>, = v₂ × t

The location of block <em>B</em>, after 3 s is x₂ = 10 m/s × 3 s = 30 m

The center of mass of two masses are given as follows;

x_{cm} = \dfrac{m_1 \cdot x_1 +m_2\cdot x_2}{m_1 + m_2}

x_{cm} = \dfrac{8  \times0 + 16 \times  30}{8 + 16} = 20

The center of mass of the two objects is at at the position x = <u>20 m</u> (from block <em>A</em>)

Learn more about the center of mass here:

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3 years ago
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Vitek1552 [10]

Answer:

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