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givi [52]
4 years ago
11

How is it possible for one electrically neutral atom to exert an electrostatic force on other electrically neutral atom?

Physics
1 answer:
Free_Kalibri [48]4 years ago
8 0

Answer:

Explained

Explanation:

Although Atom are electrically neutral. But atom atom is combination of nucleus and electrons. The nucleus of the atom is composed neutron and positively charged protons. On the outside of nucleus at some distance are the electrons which are negatively charged. So, there is difference in position of the two differently charge species. So, this way a electrically neutral atom can exert a electrostatic force on other electrically neutral atom

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The wave height is equal to twice the _____.wave period wave height wave amplitude wave velocity wavelength
Archy [21]

The wave height is equal to twice the amplitude of the wave.

The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.

The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.

Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.

Learn more here:brainly.com/question/21431500

4 0
3 years ago
What is the critical angle for light traveling from crown glass (n = 1.52) into water (n = 1.33)?
Flauer [41]

Answer:

61 degrees, I just did the test.

Explanation:

6 0
3 years ago
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Given a temperature of 300 Kelvin, what is the approximate temperature in degrees Celsius?
S_A_V [24]
<span>Jun 16, 2012 - Given a temperature of 300 Kelvin, what is the approximate temperature in degrees Celsius? –73°C 27°C 327°C 673°C.</span><span>
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3 0
4 years ago
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What is the escape velocity from a planet with a mass that is 10.8% Earths mass and a size that is 53% Earths radial size?
DENIUS [597]

The escape velocity from the planet is 5052 m/s

Explanation:

The formula to calculate the escape velocity from a planet is:

v=\sqrt{\frac{2GM}{R}}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

M is the mass of the planet

R is the radius of the planet

For Earth,

M_E=5.98\cdot 10^{24} kg is the mass

R_E=6.37\cdot 10^6 m is the radius

Here we have a planet that:

- its mass is 10.8% of that of Earth, so

M=0.108M_E

- its radius is 53% of that of Earth, so

R=0.53 R_E

Substituting everything into the first equation, we find the escape velocity from this planet:

v=\sqrt{\frac{2G(0.108M_E)}{0.53R_E}}=\sqrt{\frac{2(6.67\cdot 10^{-11})(0.108)(5.98\cdot 10^{24})}{(0.53)(6.37\cdot 10^6)}}=5052 m/s

#LearnwithBrainly

4 0
3 years ago
A small marble attached to a massless thread is hung from a horizontal support. When the marble is pulled back a small distance
s2008m [1.1K]

Answer:

f' = 2 f

Explanation:

The frequency of the pendulum that swings in simple harmonic motion is given by :

f={2\pi}\sqrt{\dfrac{l}{g}}

Where

l is the length of pendulum

g is the acceleration due to gravity

If the length of the thread is increased by a factor of 4, such that, l' = 4 l, let f' is the new frequency such that,

f'={2\pi}\sqrt{\dfrac{l' }{g}}

f'={2\pi}\sqrt{\dfrac{4l}{g}}

f'=2\times {2\pi}\sqrt{\dfrac{l}{g}}

f' = 2 f

So, the new frequency of the pendulum will become 2 time of initial frequency. Hence, the correct option is (b) "2f"

3 0
3 years ago
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