Answer:
![T_C>T_B>T_A>T_D](https://tex.z-dn.net/?f=T_C%3ET_B%3ET_A%3ET_D)
Explanation:
Now we calculate the torque in each case:
A.
Given:
Force applied to the lever arm, ![F=5\ N](https://tex.z-dn.net/?f=F%3D5%5C%20N)
distance from the pivot, ![r=1\ m](https://tex.z-dn.net/?f=r%3D1%5C%20m)
angle of application, ![\theta=30^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D30%5E%7B%5Ccirc%7D)
Torque:
![T_A=5\times 1\times sin\ 30^{\circ}](https://tex.z-dn.net/?f=T_A%3D5%5Ctimes%201%5Ctimes%20sin%5C%2030%5E%7B%5Ccirc%7D)
![T_A=2.5\ N.m](https://tex.z-dn.net/?f=T_A%3D2.5%5C%20N.m)
B.
Given:
mass moment of inertia of a disc, ![I=0.5\ kg.m^2](https://tex.z-dn.net/?f=I%3D0.5%5C%20kg.m%5E2)
acceleration of the disc, ![\alpha=10\ rad.s^{-2}](https://tex.z-dn.net/?f=%5Calpha%3D10%5C%20rad.s%5E%7B-2%7D)
Torque:
![T_B=I.\alpha](https://tex.z-dn.net/?f=T_B%3DI.%5Calpha)
![T_B=0.5\times 10](https://tex.z-dn.net/?f=T_B%3D0.5%5Ctimes%2010)
![T_B=5\ N.m](https://tex.z-dn.net/?f=T_B%3D5%5C%20N.m)
C.
force applied to the lever, ![F=10\ N](https://tex.z-dn.net/?f=F%3D10%5C%20N)
distance of lever arm, ![r=0.6\ m](https://tex.z-dn.net/?f=r%3D0.6%5C%20m)
angle of application of force, ![\theta = 90^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2090%5E%7B%5Ccirc%7D)
Torque:
![T_C=F.r.sin\ \theta](https://tex.z-dn.net/?f=T_C%3DF.r.sin%5C%20%5Ctheta)
![T_C=10\times 0.6\times sin\ 90^{\circ}](https://tex.z-dn.net/?f=T_C%3D10%5Ctimes%200.6%5Ctimes%20sin%5C%2090%5E%7B%5Ccirc%7D)
![T_C=6\ N.m](https://tex.z-dn.net/?f=T_C%3D6%5C%20N.m)
D.
mass moment of inertia of a disc, ![I=1\ kg.m^2](https://tex.z-dn.net/?f=I%3D1%5C%20kg.m%5E2)
acceleration of the disc, ![\alpha=1\ rad.s^{-2}](https://tex.z-dn.net/?f=%5Calpha%3D1%5C%20rad.s%5E%7B-2%7D)
Torque:
![T_D=I.\alpha](https://tex.z-dn.net/?f=T_D%3DI.%5Calpha)
![T_D=1\times 1](https://tex.z-dn.net/?f=T_D%3D1%5Ctimes%201)
![T_D=1\ N.m](https://tex.z-dn.net/?f=T_D%3D1%5C%20N.m)