Answer:
the formula of mechanical advantage is
MA = load / effort
VR = effort distance / load distance
hope it is helpful to you
-- We know that the y-component of acceleration is the derivative of the
y-component of velocity.
-- We know that the y-component of velocity is the derivative of the
y-component of position.
-- We're given the y-component of position as a function of time.
So, finding the velocity and acceleration is simply a matter of differentiating
the position function ... twice.
Now, the position function may look big and ugly in the picture. But with the
exception of 't' , everything else in the formula is constants, so we don't even
need any fancy processes of differentiation. The toughest part of this is going
to be trying to write it out, given the text-formatting capabilities of the wonderful
envelope-pushing website we're working on here.
From the picture . . . . . y (t) = (1/2) (a₀ - g) t² - (a₀ / 30t₀⁴ ) t⁶
First derivative . . . y' (t) = (a₀ - g) t - 6 (a₀ / 30t₀⁴ ) t⁵ = (a₀ - g) t - (a₀ / 5t₀⁴ ) t⁵
There's your velocity . . . /\ .
Second derivative . . . y'' (t) = (a₀ - g) - 5 (a₀ / 5t₀⁴ ) t⁴ = (a₀ - g) - (a₀ /t₀⁴ ) t⁴
and there's your acceleration . . . /\ .
That's the one you're supposed to graph.
a₀ is the acceleration due to the model rocket engine thrust
combined with the mass of the model rocket
'g' is the acceleration of gravity ... 9.8 m/s² or 32.2 ft/sec²
t₀ is how long the model rocket engine burns
Pick, or look up, some reasonable figures for a₀ and t₀
and you're in business.
The big name in model rocketry is Estes. Their website will give you
all the real numbers for thrust and burn-time of their engines, if you
want to follow it that far.
Answer:
962 rpm.
Explanation:
given,
angular acceleration = 190 rad/s²
initial angular speed = 0 rad/s
final angular speed = 7200 rpm
=
=
we need to calculate the revolution of disk after 10 s.
time taken to reach the final angular velocity
using equation of angular motion


t = 4 s
rotation of wheel in 4 s



θ = 1520 rad


now, revolution of the disk in next 6 s
angular velocity is constant


θ_f = 6044 rad
θ_f = 
revolution of the computer hard disk
θ_f = 962 rpm.
total revolution of the computer disk after 10 s is equal to 962 rpm.
Answer:695.5 N
Explanation:
mass of child 
Length of chain 
Tension in each chain 
(a)Tension at bottom point 
At lowest Point





(b)Force exerted by Seat will be Equal to Normal reaction




Answer:
The acceleration will become 9/2 times.
a' =9/2 a
Explanation:
We know that acceleration of a particle when it is moving in the circular path is given as

r=radius
ω= angular speed
If the speed ω '= 3 ω
If the radius ,
The final acceleration =a'






Therefore the acceleration will become 9/2 times.