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Travka [436]
2 years ago
9

Hii Happy New year can you all please answer this​

Physics
1 answer:
mel-nik [20]2 years ago
4 0

Answer:

truuuuuuuuuuuuueeeeeeeee

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A planet of mass 7.00 1025 kg is in a circular orbit of radius 6.00 1011 m around a star. The star exerts a force on the planet
BARSIC [14]

Answer:

A) 1.88 * 10^17 m

B) 1.22 * 10^34 J

C) 1.95 * 10^34 J

Explanation:

Parameters given:

Mass of planet = 7.00 * 10^25 kg

Radius of orbit = 6.00 * 10^11 m

Force exerted on planet = 6.51 * 10^22 N

Velocity of planet = 2.36 * 10^4 m/s

A) The distance traveled by the planet is half of the circumference of the orbit (which is circular).

The circumference of the orbit is

C = 2 * pi * R

R = radius of orbit

C = 2 * 3.142 * 6.0 * 10¹¹

C = 3.77 * 10¹² m

Hence, distance traveled will be:

D = 0.5 * 3.77 * 10¹²

D = 1.88 * 10 ¹² m/s

B) Work done is given as:

W = F * D

W = 652 * 10²² * 1.88 * 10¹¹

W = 1.22 * 10³⁴ J

C) Change in Kinetic energy is given as:

K. E. = 0.5 * m * v²

K. E. = 0.5 * 7 * 10^25 * (2.36 * 10^4)²

K. E. = 1.95 * 10³⁴ J

7 0
3 years ago
Calculate the area of a square with a length of 5cm
mihalych1998 [28]

Answer:

25cm^2

Explanation:

area of square = side × side

length of side given = 5

area of this square = 5× 5

= 25cm^2

hope it helps

6 0
3 years ago
Read 2 more answers
What is the answer to life?
taurus [48]
The answer to life is how ever you make it...... you can do anything with life that you would like.................. But make your choices worth it......
6 0
3 years ago
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Two point charges exert a 5.00 N force on each other. What will the force become if the distance between them is increased by a
weeeeeb [17]

Answer:

force becomes one - ninth

Explanation:

According to Coulomb's law in electrostatics, two charges can exert a force of attraction or repulsion on each other which is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

Here both the charges remains same but the distance is variable.

So, we can say that

F \alpha \frac{1}{d^{2}}    .... (1)

Where d be the distance between the tow charges

As the distance between two charges increases by factor of three, let the new force be F'.

F' \alpha \frac{1}{9d^{2}}   .... (2)

Divide equation (2) by equation (1), we get

\frac{F'}{F}=\frac{d^{2}}{9d^{2}}

F'=\frac{F}{9}

Thus, the force becomes one - ninth times the initial force.

6 0
3 years ago
What is the speed of a car traveling 100 m in 20 s?
Ludmilka [50]

Answer: To answer this question, we will need the following equation: SPEED = DISTANCE/TIME (A multiplication and division triangle will be shown)i) The speed of the car is calculated by doing 100 metres/ 20 seconds which gives us 5 metres per second. ii) Rearranging the equation earlier, we can make the distance the subject of the equation so that we get SPEED x TIME = DISTANCE. We worked out the speed and the time was given as 1 minute 40 seconds but we cannot plug in the numbers yet as the time has to be converted to units of seconds (because our speed is in meters per second). 1 minute 40 seconds = 60 seconds + 40 seconds = 100 secondsWe then plug in the numbers to get the distance travelled = 5 metres per second x 100 seconds = 500 metres.

Explanation:

3 0
3 years ago
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