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kakasveta [241]
3 years ago
9

How do modern periodic table arranged

Chemistry
1 answer:
pychu [463]3 years ago
4 0
In the modern periodic table, the elements are arranged according to their atomic number - not their relative atomic mass.



In the periodic table the elements are arranged into:

rows, called periods, in order of increasing atomic number
vertical columns, called groups, where the elements have similar properties

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The pressure of a sample of ch4 gas (6.022 g) in a 30.0 l vessel at 402 k is __________ atm
mel-nik [20]
From  ideal  gas  equation,  that  is   PV =nRT
P=nRT/V
n  is  the  number  of  moles
the molar  mass  of  CH4 =12+4=16
R  is the gas  contant (0.0821 atm/mol/k)
n= 6.022/16=0.376 moles
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4 0
3 years ago
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Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the
Alecsey [184]

Explanation:

The chemical equation is as follows.

      \frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)

And, the given enthalpy is as follows.

    \frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g);  \Delta H = 102.5 kJ

    Cl-Cl = 243 kJ/mol,      O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

   \Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}

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    102.5 = (\frac{1}{2})x + 498 - 486

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Now, total bond enthalpy of per mole of ClO is calculated as follows.

       \Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})

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Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

8 0
3 years ago
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3 years ago
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4 years ago
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Answer:

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