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3 years ago

A bicycle consists of which types of simple machines? Check all that apply. lever

2 answers:

6 0

A bike is compound machine.This means that it is made up of a bunch of different simple machines. Screws are used to hold the pieces together. The wheel of a bicycle is a wheel and axle. The pedals are also examples of this simple machine. The pedals are attached to a lever that turns a pulley.

Mnenie [13.5K]3 years ago

6 0

Answer:

Lever, pulley and wheel and axle are the types of machine it's grouped to

Explanation:

The wheel and axle is a simple machine that works by reducing friction in trying to move a load. This is seen in the Tyre of the bicycle

Pulley is a simple machine that creates a mechanical advantage and supports the changing of direction for a rope or cable. This is seen in the chain of the bicycle

Levers attached to the bike's pedals are pushed down to direct force into the pulley system.

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In short, Your Answer would be "True"

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3 years ago

Mixing baking soda with vinegar is an example of an oxidation-reduction

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Explanation:

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3 years ago

Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. drag each item to the a

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4 years ago

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The area of the pond is approximately equal to the area of a circle with radius 297m. Find the mass of the ice. Answer in kilogr

True [87]

Answer:

mass of the ice is 254980463.8T kg

where T is the value of the thickness omitted in the question.

Explanation:

The ice on Walden Pond is .......... thick. The area of the pond is approximately equal to the area of a circle with radius 297 m. Find the mass of the ice. Answer in kg.

The value of the thickness of the ice T is omitted, but I will show the solution, and the real answer can be gotten by multiplying the final calculated answer here by the thickness of the ice omitted.

Given the radius of the equivalent circle of the ice = 297 m'

the area of the ice can be gotten from area A = $\pi r^{2}$ = $3.142*297^{2}$ = 277152.678 m^2

recall that the density of ice p ≅ 920 kg/m^3

also,

density of ice p = (mass of ice, m) ÷ (volume of ice, v)

i.e p = m/v

and,

m = pv

substituting the value of the density of water p into the equation, we have,

mass of the ice, m = 920v ....... equ 1

The volume of the ice above will be = (area of the ice, A) x (thickness of the ice, T)

i.e v = AT

substituting the value of area A into the equation, we have

v = 277152.678T ......equ 2

substitute value of v into equ 1

mass of the ice, m = 920 x (277152.678T)

mass of the ice, m = 254980463.8T kg

where T is the thickness of the ice

NB: To get the mass, multiply this answer with the thickness T given in the question.

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3 years ago