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2 years ago

An inventor claims to have developed a new perfume that lasts a long time because it doesn't evaporate. Comment on this claim.

Chemistry

1 answer:

zaharov [31]2 years ago

3 0

Answer:

Explanation:

Perfume needs to evaporate in order to smell. If this perfume didn't evaporate, it would stay as a liquid and never smell.

It wouldn't be D, as no toxic perfumes is sold.

It's not A because perfume doesn't have to be pressurized in order to not evaporate.

It's not B, as it is a hasty conclusion to the claim. Plus, if the perfume did have an odor, even while not evaporating, the sales would be low as the product is that good.

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In which of the following compounds is the mass ratio of chromium to oxygen closest to 1.62 to 1.00?

ohaa [14]

Answer:

The answer to your question is letter A

Explanation:

Data

Mass ratio 1.62 to 1.00

Atomic mass Cr = 52 g

Atomic mass O = 16

Process

1.- Calculate the proportion Chromium to Oxygen to each possible solutions

a) CrO₃ = $\frac{52}{16 x 3} = \frac{52}{48} = 1.08$

b) CrO₂ = $\frac{52}{16 x 2} = \frac{52}{32} = 1.63$

c) CrO = $\frac{52}{16} = 3.25$

d) Cr₂O = $\frac{52 x 2}{16} = \frac{104}{16} = 6.5$

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3 years ago

What objects in the solar system are larger

GalinKa [24]

Answer:

Explanation:

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2 years ago

Commercial manufacturers produce nitric acid (HNO3) by the Ostwald process. The process requires three steps:

Shkiper50 [21]

Answer:

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Explanation:

5 0

3 years ago

Please help, I lost my previous tutor just when she was explaining the answer

TEA [102]

Answer:

HCO₂/H₂O is not the acid-base conjugate pair.

Explanation:

<em>Acid and conjugate base pairs differ by an H+ ion.</em>

Neither HCO₂ nor H₂O has lost or gained protons.

The conjugate acid of H₂O is H₃O⁺

The conjugate base of HCO₃⁻ is CO₃²⁻

[A conjugate acid has one more H⁺ than its base]

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2 years ago

At a given temperature, the elementary reaction A --->B in the forward direction is first order in A with a rate constant of

Pani-rosa [81]

Answer:

The value of the equilibrium constant for the reaction A ⇒ B is Kc = 1.72 × 10³.

The value of the equilibrium constant for the reaction B ⇒ A is K'c = 5.81 × 10⁻⁴.

Explanation:

For the reaction A ⇒ B, the equilibrium constant (Kc) is equal to the forward rate constant (kf) divided by the reverse rate constant (ki).

$Kc=\frac{kf}{ki} =\frac{1.60 \times 10^{2} s^{-1} }{ 9.30 \times 10^{-2} s^{-1}} =1.72 \times 10^{3}$

If we consider the inverse reaction B ⇒ A, its equilibrium constant (K'c) is the inverse of the forward reaction equilibrium constant.

$K'c=\frac{1}{Kc} =\frac{1}{1.72 \times 10^{3} } =5.81 \times 10^{-4}$

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3 years ago