Answer:

Explanation:
The Rydberg formula can be extended for use with any hydrogen-like chemical elements, that is to say with only one electron being affected by effective nuclear charge. So, in this case, we can calculate the wavelenghts of the emitted photons using this formula:

Where R is the Rydberg constant of the element, Z its atomic number,
is the lower energy level and
the upper energy level of the electron transition. Recall that the ground state is denoted as n=1.

Answer:
C. are often metals
and
D. have high conductivity
The Electromagnetic ave that is about the size of humans is : A typical micro waves have around 14 inches ( 1.1 meter) in height.
This is very similar to the height of human right before we hit puberty (around 9 - 10 years old)
Answer:
t = Δa / v
Explanation:
To know which option is not true, we shall fine a relationship between acceleration (a), velocity (v), time (t) and radius (r). This is illustrated below:
Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as shown below:
Acceleration = change in velocity / time
a = Δv / t ..... (1)
But
Δv = v₂ – v₁
Substitute the value of Δv into equation (1)
a = Δv / t
a = v₂ – v₁ / t ....... (2)
From equation (1), make Δv the subject of the equation.
a = Δv / t
Cross multiply
Δv = at .... (3)
From equation (1), make t the subject of the equation.
a = Δv / t
Cross multiply
at = Δv
Divide both side by a
t = Δv /a ...... (4)
From circular motion, centripetal's force is given by:
F = mv²/r
F = ma꜀
Therefore,
ma꜀ = mv²/r
Cancel out m
a꜀ = v²/r
SUMMARY:
a = Δv / t
a = v₂ – v₁ / t
Δv = at
t = Δv /a
a꜀ = v²/r
Considering the options given in question above, t = Δa / v is not a true statement.
Answer:
The angle of reflection is "60°".
Explanation:
The given values are:
Light from monochromatic source,
= 560 nm
Angle of incidence,
= 60°
Surface of fused quartz (n),
= 1.56
Whenever a light ray was indeed occurring at a flat surface, it should be the law or concept of reflection which contains this same rays of light, the reflected ray as well as the "normal" ray at either the mirror surface.
According to the above law,
⇒ 
then,
⇒ 