Answer:
The force originates from the tires. Tires accelerate the car. The car interior in turn accelerates the air inside the car by providing a pushing force. Thus it is the car read windows, seats and side windows that push the air forward causing it to accelerate.
Explanation:
The air inside the car is being forced forward by the car interior. This includes the rear windows, seats, side windows etc.
This accelerating force originates from the tires, and makes the car interior accelerate with the car. The air inside (since it has no direct connection to the tires) is then pushed forward by the windows, seats etc.
Answer:
Un automóvil en movimiento en una carretera.
Una piedra rodando por una colina.
Un hierro que se empuja a través del materia
Vegetables has moisture and during rise in the temperature the gas sealed and generated from moisture expands. Gas when heated or experience rise in temperature expands.
Answer:
decibel gain is 10 db
Explanation:
given data
voltage v1 = 5 volts
voltage v2 = 15 volts
to find out
decibel gain
solution
we have given that 5 volt voltage that is increase to 15 volts
so
we know here decibel gain formula that is
decibel gain = 20 log(v2/v1) ....................1
put here value of v1 and v2 in equation 1
decibel gain = 20 log(15/5)
decibel gain = 20 log3
decibel gain = 20 × 0.4771
decibel gain = 9.54 db = approx 10 db
so decibel gain is 10 db
This question is incomplete, the complete question is;
The Figure shows a container that is sealed at the top by a moveable piston, Inside the container is an ideal gas at 1.00 atm. 20.0°C and 1.00 L.
"What will the pressure inside the container become if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant?"
Answer:
the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant
Explanation:
Given that;
P₁ = 1.00 atm
P₂ = ?
V₁ = 1 L
V₂ = 1.60 L
the temperature of the gas is kept constant
we know that;
P₁V₁ = P₂V₂
so we substitute
1 × 1 = P₂ × 1.60
P₂ = 1 / 1.60
P₂ = 0.625 atm
Therefore the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant
