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Paladinen [302]

3 years ago

14

2 Bikers Rode at a constant speed on a 150 meter track.The data here show each bikers distance for a certain part of the race.Wh

o won the race and by how much

2 answers:

Fittoniya [83]3 years ago

7 0

Biker two won the race by 1 second ( hope this is helpful ).

kykrilka [37]3 years ago

4 0

Answer:

Student 2 won the race by 1 second

Explanation:

Took the quiz :D

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The image messed up but you get the point. Don't be mean and just answer to get the points, please and thank you.

Katarina [22]

Answer:

Answer is A, it will pass through to focal point after reflecting.

Explanation:

I had the same question in a test, Sorry that you had to do this question in middle school.

4 0

3 years ago

What are the coefficients in this expression?

skad [1K]

6 and $\frac{1}{3}$

Explanation:

The expression:

6a - $\frac{3}{4} + 7.5 - \frac{b}{3}$

A coefficient is a numerical constant usually placed before a variable in an expression.

They are used to multiply variables.

Given equation is;

$6a - \frac{3}{4} + 7.5 - \frac{b}{3}$

There are two variables in this expression which are;

a and - b

$6 (a) - \frac{3}{4} + 7.5 - b (\frac{1}{3} )$

The coefficients in this expression are:

6 and $\frac{1}{3}$

learn more:

Quadratic equation brainly.com/question/1357167

#learnwithBrainly

7 0

3 years ago

Read 2 more answers

Explain what an exoskeleton is and what it is made of.

barxatty [35]

A rigid outer lair covering for the body in some invertebrate animals, especially arthropods, providing both support and protection. and is made of <span>chitin, a substance produced by many non-arthropods as well.</span>

8 0

3 years ago

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The sound from a loud speaker has an intensity level of 80 db at a distance of 2.0m. Consider the speaker to be a point source,

Tamiku [17]

Answer:

2.83m

Explanation:

The information that we have is

Intensity at 2.0 m: $I=80dB$ and $r_{1}=2m$

we need an intensity level of: $I_{2}=40dB$

thus, we are looking for the distance $r_{2}$ .

which we can find with the law for intensity and distance:

$(\frac{r_{2}}{r_{1}} )^2=\frac{I_{1}}{I_{2}}$

we solve for $r_{2}$ :

$\frac{r_{2}}{r_{1}}=\sqrt{\frac{I_{1}}{I_{2}} }\\\\r_{2}=r_{1}\sqrt{\frac{I_{1}}{I_{2}} }$

and we substitute the known values:

$r_{2}=(2m)\sqrt{\frac{80dB}{40dB} }\\\\r_{2}=(2m)\sqrt{2}\\ r_{2}=2.83m$

at a distance of 2.83m the intensity level is 40dB

5 0

3 years ago

The stone in the accompanying ﬁgure can be carried from the bottom to the top of a cliff by various paths. Which path requires m

maxonik [38]

The choice of path should make no difference. The work should depend only on the end points and not on the route between them. But just to make sure, could we please have a look at the accompanying figure ?

5 0

3 years ago

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