3 years ago

Use the element symbols to write the electronic configuration Na

1 answer:

8 0

Electron Configuration is the distribution of electrons of an atom or molecule in an atomic or molecular orbitals.

So Na, or Sodium has 11 electrons, so the number should add up to 11

Na: 1s² 2s² 3p⁶ 3s¹

Hope this helps!

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This feature of a volcano is called an____________________which releases heated ash and Tephra through its column generating its

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Answer:

Volcanic Eruption releases heated ash and Tephra through its column generating its own lightning.

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3 years ago

A hypothetical metal crystallizes with the face-centered cubic unit cell. The radius of the metal atom is 234 picometers and its

AleksAgata [21]

Answer:

$\delta=101.13 g/cm^3$

Explanation:

As can be seen in the Figure in a face-centered cubic unit cell you have:

Six halves of atoms
Eight 1/8 of atom (1 in each corner)

In total:

$n_{atom}=6*0.5+8*\frac{1}{8}=4 atoms$

Now, each side of the cell is 234 picometers (2.34e-8 cm) long

$V_{cell}=L^3=(2.34e^{-8} cm)^3$

$V_{cell}=1.28*10^{-23}cm^3$

Atoms per cm3:

$n=\frac{4 atoms}{1.28*10^{-23}cm^3}$

$n=3.12*10^{23} atoms/cm^3$

Expressing in mass:

$\delta=3.12*10^{23} atoms/cm^3* \frac{1 mol}{6.022*10^{23}}*195.08 g/mol$

$\delta=101.13 g/cm^3$

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3 years ago

3. If we remember seeing something happen, we can trust that it happened just as we think it did. True or False

djverab [1.8K]

$\huge{ \underbrace{ \overbrace{True}}}$

$\huge\mathfrak\purple{Hope \: it \: helps}$

Note : Because Many of My Dreams came true and I realized.

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3 years ago

Calculate the ph of a buffer that is 0.225 m hc2h3o2 and 0.162 m kc2h3o2. the ka for hc2h3o2 is 1.8 Ã 10-5. 4.60 9.26 4.74 4.89

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Answer:

The pH of the buffer solution is 4.60.

Explanation:

Concentration of acid = $[HC_2H_3O_2]=0.225 M$

Concentration of salt = $[KC_2H_3O_2]=0.162 M$

Dissociation constant = $K_a=1.8 \times 10^{-5}$

The pH of the buffer can be determined by Henderson-Hasselbalch equation:

$pH=pK_a+\log\frac{[salt]}{[acid]}$

$pH=-\log[1.8 \times 10^{-5}]+\log\frac{0.162 M}{0.225 M}$

pH = 4.60

The pH of the buffer solution is 4.60.

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3 years ago

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Modify lysine, below, to show the predominant form at pH 7.

Akimi4 [234]

Basically, both amine groups will be pronated while the carboxylic acid will be depronated due to their pkas.

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3 years ago

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