Question

70-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 844 N. What is the acceleration of the elevator?

Answer 1

Answer : The acceleration of the elevator is, $2.25m/s^2$

Explanation :

Formula used to calculate the acceleration of the elevator is:

$F=mg+ma\\\\ma=F-mg\\\\a=\frac{F-mg}{m}$

where,

F = force = 844 M

m = mass of man = 70 kg

g = acceleration due to gravity = $9.8m/s^2$

a = acceleration of the elevator = ?

Now put all the given values in the above formula, we get:

$a=\frac{F-mg}{m}$

$a=\frac{844N-(70kg\times 9.8m/s^2)}{70kg}$

$a=2.25m/s^2$

Thus, the acceleration of the elevator is, $2.25m/s^2$