2NH3(g) = N2(g) + 3H2(g)
Before decomposed :
P NH3 = 2.7 atm
After decomposed :
P N2 = 0.54 atm
P H2 = P N2 / 3 = 0.54 / 3 = 0.18 atm
P NH3 = 2.7 - 2(0.18) = 2.34 atm
Pressure equilibrium constant :
Kp = (P N2)(P H2)³ / (P NH3)²
Kp = (0.54)(0.18)³ / (2.34)²
Kp = 5.75 × 10^(-4)
Answer:
Explanation:
mass of the solution m = 1.6 + 75 = 76.6 g
fall in temperature = 25 - 23.34 = 1.66°C
heat absorbed = mass x specific heat x fall in temperature
= 76.6 x 1.66 x 4.18
= 531.5 J .
= .5315 kJ .
mol weight of ammonium nitrate = 80 g
heat absorbed by 1.6 g = .5315 kJ
heat absorbed by 80 g or one mole = 26.575 kJ
enthalpy change ΔH = +26.575 kJ
b )
enthalpy of hydration = 2630 kJ / mol
lattice energy = enthalpy of hydration + enthalpy change
= 2630 + 26.575
= 2656.575 kJ .
Answer:
C. HCI(g)
Explanation:
The following equation between hydrogen gas (H2) and oxygen gas (O2) is given below:
H2(g) + Cl2(g) ►
Based on these unbalanced equation, the products of the reaction was not given, however, if one molecule of hydrogen and oxygen combine, hydrogen chloride (HCl) should be produced as the product of the reaction as in:
H2(g) + Cl2(9) ► 2HCl(g)
P1V1 = P2V2
P1 = 0.60 atm
V1 = 10.2 L
P2 = ?
V2 = 3.0 L
Solve for P2 —> P2 = P1V1/V2 = (0.60 atm)(10.2 L) / (3.0 L) = 2.04 atm
