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leva [86]
3 years ago
10

Sally walks 10 meters forward and then 5 meters backwards. a) What is Sally’s displacement? Give magnitude (#) and direction – d

isplacement is a vector. b) What is Sally’s distance? Give magnitude (#) only – distance is a scalar.
Physics
1 answer:
ra1l [238]3 years ago
8 0

consider the forward direction as positive and backward direction as negative. hence displacement in froward direction will be taken as positive and displacement in backward direction will be taken as negative.

\underset{d_{1}}{\rightarrow}\\ = displacement in forward direction = 10 meters

\underset{d_{2}}{\rightarrow}\\ = displacement in backward direction = - 5  meters

\underset{d_{net}}{\rightarrow}\\ = net displacement

net displacement is given as

\underset{d_{net}}{\rightarrow}\\ = \underset{d_{1}}{\rightarrow}\\ + \underset{d_{2}}{\rightarrow}\\

\underset{d_{net}}{\rightarrow}\\ = 10 + (- 5)

\underset{d_{net}}{\rightarrow}\\ =  5 meters

Since net displacement is positive , and forward is positive direction of motion.

hence the displacement is 5 meters in forward direction.


b)

d₁ = distance traveled in forward direction = 10 meters

d₂ = distance traveled in backward direction = 5 meters

D = total distance traveled

total distance traveled is given as

D = d₁ + d₂

D = 10 + 5

D = 15 meters

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now the distance before they stop with respect to each other is given by

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Part b)

Distance traveled by car before it stops is given by

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Part c)

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