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OleMash [197]
3 years ago
8

9. A wave front has the form of a

Physics
1 answer:
AVprozaik [17]3 years ago
8 0
A wave front has the form of a surface of a sphere
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If you're driving towards the sun late in the afternoon, you can reduce the glare from the road by wearing sunglasses that permi
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Two vectors A and B are at right angles to each other. The magnitude of A is 3.00. What should be the length of B, so that the m
AfilCa [17]

Answer: length of B =4.00

Explanation:

for  the vectors A and B and the angle between them as  x.

Magnitude of the sum of A and B is  given as = √(A²+B²+2ABcosx

where

Magnitude of A  = 3.00

Magnitude of the sum of A and B is  5.00

5.00=√(A²+B²+2ABcos90°

5.00= √3² +b² +0

5²= 3² +b²

25=9+b²

b²= 25-9

b² = 16

b=  √16

b= 4

7 0
3 years ago
A machine has a mechanical advantage of 4.5. What force is put out by the machine if the force applied to the machine is 800 N?
Ghella [55]

If the machine's mechanical advantage is 4.5, that means that

Output force = (4.5) x (Input force) .

We know the input force, and we need to find the output force.  Rather than wander around the room looking at the floor while our hair smolders, let's try putting the numbers we know into the equation I wrote up there.  OK ?

Output force = (4.5) x (Input force)

Output force = (4.5) x (800 N)

Now dooda multiplication:

<em>Output force = 3,600 N</em> .  

That's exactly what the question asked for.  So we're done !

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3 years ago
Red fox
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In a food pyramid, the organism that has the least amount of total energy available is the one that is in the bottom or last. In this case, given the list of organisms above, the organism that would have the least amount of total energy available would be the RED FOX. The answer is option A. Hope this answer helps.
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3 years ago
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What mass of steam at 100°C must be mixed with 119 g of ice at its melting point, in a thermally insulated container, to produce
N76 [4]

Answer:M=27.92\ gm

Explanation:

Given

mass of ice m=119\ gm

Final temperature of liquid T_f=57^{\circ}C

Specific heat of water c=4186\ J/kg-K

Latent heat of fusion L=333\ kJ/kg

Latent heat of vaporization L_v=2256\ kJ/kg

Suppose M is the mass of steam at 100^{\circ} C

Heat required to melt ice and convert it to water at 57^{\circ}C

Q_1=mL+mc(T_f-0)

Heat released by steam

Q_2=ML_v+Mc(100-T_f)

Q_1 and Q_2 must be equal as the heat gained by ice is equal to Heat released by steam

Q_1=Q_2

\Rightarrow mL+mc(T_f-0)= ML_v+Mc(100-T_f)

\Rightarrow M=\dfrac{m[L+c\times T_f]}{L_v+c(100-T_f)}

\Rightarrow M=\dfrac{119[333\times 10^3+4186\times 57]}{2256\times 10^3+4186\times (100-57)}

\Rightarrow M=119\times 0.2346

M=27.92\ gm

7 0
3 years ago
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