Answer:
a) rate law1 = k[NO2]²
b) rate law2 = k[NO][O3]
Explanation:
NO2(g) + CO(g) → NO(g) + CO2(g)
NO(g) + O3(g) → NO2(g) + O2(g)
When [NO2] in reaction 1 is doubled, the reaction quadruples
Rxn is second order.
rate law1= [NO2]^a [CO]^b
rate law1= [NO2]² [CO]^0
rate law1 = k[NO2]²
When [NO] in reaction 2 is doubled, the rate doubles.
Rxn is first order
The ratio is 1:1
this makes the rate law2 = k[NO][O3]
A polar bonds share electrons meaning they are a convenient bond
Answer:
Velocity = 120 km/h in north
Speed = 120 km/h
Explanation:
Given data:
Distance = 300 km north
Time taken = 2.5 hr
Speed and velocity = ?
Solution:
Speed = distance / time
Speed = 300 km / 2.5 h
Speed = 120 km/h
Velocity = change in position / change in time
Velocity = 300 km north / 2.5 hr
Velocity = 120 km/h in north
Answer: Special care is required to prepare a solution of sodium hydroxide or NaOH in water because considerable heat is liberated by the exothermic reaction. The solution may splatter or boil. Here is how to make a sodium hydroxide solution safely, along with recipes for several common concentrations of NaOH solution.
Explanation:
Hope this helps!
