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Viefleur [7K]
3 years ago
12

What's the frequency of 506 nanometers

Chemistry
1 answer:
Dominik [7]3 years ago
7 0
It would be in the visible light wavelength, specifically in the color green.
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In ionic bonding, atoms__.
Nutka1998 [239]
In ionic bonding, atoms SHARE ELECTRONS
8 0
2 years ago
Before raw data can be used as scientific evidence, it must be analyzed and summarized. One way of summarizing data is to find t
Sindrei [870]
To calculate the mean, you add up all of the data values, and then divide that sum by the *number* of values.

For instance, if you wanted to find the mean score at a home run derby, and you’re given the following numbers for home runs scored by each player:

5, 4, 6, 5, 3, 1

You could calculate the mean by adding all of the score up

5 + 4 + 6 + 5 + 3 + 1 = 24

And dividing by the number of hitters (in this case, 6)

24 / 6 = 4

So the *mean score* of the home run derby would be 4.

7 0
3 years ago
How many miles of lead are equal to 9.51 x 10^3 g Pb?
Lemur [1.5K]
Molar mass Pb = 207.2 g/mol

1 mole Pb ------------- 207.2
? mole Pb ------------ 9.51 x 10³

moles = 9.51 x 10³ * 1 / 207.2

moles = 9.51 x 10³ / 207.2

= 45.89 moles

hope this helps!

7 0
3 years ago
Please helpppp ASAP !!!!Which phase changes require the addition of energy to happen, which phase changes require the removal of
ziro4ka [17]

Answer:

Evaporation

Explanation:

Evaporation involves a liquid becoming a gas and sublimation is the change of a solid directly to a gas. Phase changes require either the addition of heat energy or subtraction of heat energy .

6 0
3 years ago
What is the molarity (M) of the following solutions?
Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

                                      = 27 + 3(16 + 1)

                                      = 27 + 3(17) = 27 + 51

                                      = 78 g/mole

Al(OH)_3 = 78 g/mole

Given mass= 19.2 g/mole

Mole = \frac{Given\ mass}{Molar\ mass}

Mole = \frac{19.2}{78}

Moles = 0.246

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Volume = 280 mL = 0.280 L

Molarity = \frac{0.246}{0.280)}

Molarity  = 0.879 M

Molarity  = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr​

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

Mole = \frac{235.9}{119}

Moles = 1.98

Volume = 2.6 L

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Molarity = \frac{1.98}{2.6)}

Molarity = 0.762 M

Molarity = 0.76 M

4 0
3 years ago
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