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spayn [35]
4 years ago
12

Consider four objects: A, B, C, and D. If A is negatively charged and B and C attract A but repel each other, what is the charge

on B and C?
A. Both B and C are positively charged.

B. Both B and C are negatively charged.

C. B is positively charged and C is negatively charged.

D. B is negatively charged and C is positively charged.

E. Both B and C have no charge.
Physics
2 answers:
mote1985 [20]4 years ago
8 0
A Both b and c are positivly charged
kykrilka [37]4 years ago
4 0

Answer: The correct answer is "Both B and C are positively charged".

Explanation:

Same charges repel each other. There is an electrostatic force of repulsion between the same charges.

Unlike charges attract each other. There is an electrostatic force of attraction between the opposite charges.

In the given problem, consider four objects: A, B, C, and D. If A is negatively charged and B and C attract A but repel each other.

In the given question, B and C repel each other. It means that both B and C have same charge. A is negatively charged. Then, B and C have positive charge. As B and C attract A. Both B and C are positively charged.

Therefore, the option (B) is correct.

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HELP PLS i need this right now
N76 [4]

Answer:

V = 44.4 units.

Explanation:

In order to solve this problem, we must use the Pythagorean theorem. Which is defined by the following expression.

V = \sqrt{(V_{x})^{2} +(V_{y})^{2} }

where:

Vx = - 43 units

Vy = 11.1 units

Now replacing:

V=\sqrt{(-43)^{2} +(11.1)^{2} }\\V=44.4 units

7 0
3 years ago
a spring with a spring constant of 65 n/m is displaced -94cm. what is the magnitude of the force exerted by the spring
garri49 [273]

Answer:

Explanation:

F = kx = 65 N/m(0.94 m) = 61.1 = 61 N

8 0
3 years ago
Charlie pulls horizontally to the right on a wagon with a force of 37.2 N. Sara pulls horizontally to the left with a force of 2
Sidana [21]

Answer:

The work done on the wagon is 37 joules.

Explanation:

Given that,

The force applied by Charlie to the right, F = 37.2 N

The force applied by Sara to the left, F' = 22.4 N

We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :

F_n=F-F'

F_n=37.2-22.4

F_n=14.8\ N

Work done on the wagon is given by the product of net force and displacement. It is given by :

W=F_n\times d

W=14.8\ N\times 2.5\ m

W = 37 Joules

So, the work done on the wagon is 37 joules. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
Two identical masses, A and B, slide down frictionless ramps, both starting at a height of 3M above the ground. Object A slides
balu736 [363]

Answer: c. Neither, they have the same speed.

In both the cases, there will be work done by the gravitational force. Since, the gravitational force is a conservative force, its work done does not depend on the path as it only depends on the initial and final position of the objects. Since, the initial and final positions are same for both the objects, the work done by gravitational force will be same in both the cases.

Hence, Work done by gravitational force = Change in the kinetic energy

So, the kinetic energy will be same for both the object.

Since, the masses are same: Kinetic energy = \frac{1}{2}mv^2

Hence, the speed will also be same for both the objects.

Correct option: C

3 0
4 years ago
A worker drives a 0.554 kg spike into a rail tie with a 2.30 kg sledgehammer. The hammer hits the spike with a speed of 62.7 m/s
Goryan [66]

Answer:

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

Explanation:

Given

Weight of sledge hammer = 2.30 kilogram

Speed of sledge hammer = 62.7 meter per second

Kinetic energy is equal to half the product of mass and velocity square

K E = \frac{1}{2} mv^2

Substituting the value of mass and velocity, we get -

KE = 0.5 * 2.30 * 62.7^2\\KE = 4520.9835

It is given that one fourth of the energy is converted into internal energy

One fourth of kinetic energy is equal to

\frac{1}{4} * 4520.9835\\= 1130.246

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

8 0
3 years ago
Read 2 more answers
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