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spayn [35]
4 years ago
12

Consider four objects: A, B, C, and D. If A is negatively charged and B and C attract A but repel each other, what is the charge

on B and C?
A. Both B and C are positively charged.

B. Both B and C are negatively charged.

C. B is positively charged and C is negatively charged.

D. B is negatively charged and C is positively charged.

E. Both B and C have no charge.
Physics
2 answers:
mote1985 [20]4 years ago
8 0
A Both b and c are positivly charged
kykrilka [37]4 years ago
4 0

Answer: The correct answer is "Both B and C are positively charged".

Explanation:

Same charges repel each other. There is an electrostatic force of repulsion between the same charges.

Unlike charges attract each other. There is an electrostatic force of attraction between the opposite charges.

In the given problem, consider four objects: A, B, C, and D. If A is negatively charged and B and C attract A but repel each other.

In the given question, B and C repel each other. It means that both B and C have same charge. A is negatively charged. Then, B and C have positive charge. As B and C attract A. Both B and C are positively charged.

Therefore, the option (B) is correct.

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Perpetual motion machines have fascinated people especially inventors for hundreds of years before the laws of thermodynamics be
Cerrena [4.2K]

Given the fact that energy conversion is not entirely efficient, it is impossible to produce a perpetual motion machine.

<h3>What is a perpetual motion machine?</h3>

The perpetual motion machine in one that is able to work continuously without stopping. This would mean that the efficiency of this machine must that the machine is 100% efficient which violates the second law of thermodynamics.

Thus, given the fact that energy conversion is not entirely efficient and energy looses cause machines not function effectively, it is impossible to produce a perpetual motion machine.

Learn kore about a perpetual motion machine:brainly.com/question/13001849

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5 0
2 years ago
A skydiver of 75 kg mass has a terminal velocity of 60 m/s. At what speed is the resistive force on the skydiver half that when
ankoles [38]

Answer:

The speed of the resistive force is 42.426 m/s

Explanation:

Given;

mass of skydiver, m = 75 kg

terminal velocity, V_T = 60 \ m/s

The resistive force on the skydiver is known as drag force.

Drag force is directly proportional to square of terminal velocity.

F_D = kV_T^2

Where;

k is a constant

k = \frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2}

When the new drag force is half of the original drag force;

F_D_2 = \frac{F_D_1}{2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_1}{2V_{T2}^2} \\\\\frac{1}{V_{T1}^2} = \frac{1}{2V_{T2}^2}\\\\2V_{T2}^2 = V_{T1}^2\\\\V_{T2}^2= \frac{V_{T1}^2}{2} \\\\V_{T2}= \sqrt{\frac{V_{T1}^2}{2} } \\\\V_{T2}=  \frac{V_{T1}}{\sqrt{2} } \\\\V_{T2}=  0.7071(V_{T1})\\\\V_{T2}= 0.7071(60 \ m/s)\\\\V_{T2}= 42.426 \ m/s

Therefore, the speed of the resistive force is 42.426 m/s

8 0
3 years ago
How will the frequency of a wave appear to change if the source of the wave is moving toward an observer
amm1812

pitch goes up on approach ... Doppler effect

6 0
3 years ago
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Have you ever written a bio-data or an application letter? Share your experience in the
Georgia [21]

Answer:

I found the experience tasking

Explanation:

I wouldn't say it was hard, neither was it easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. Of course I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.

I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn

8 0
3 years ago
Henry ran a 100 m race. Use the graph to answer the following:
horrorfan [7]

Using the graph, which describes how Henry ran the 100m race;

a) It takes Henry 20seconds to run 100m

b) Henry's average speed over the race is; 5m/s.

According to the linear graph which describes the distance ran by Henry during the 100m race as a function of time.

a) Since the distance from start ran by Henry is plotted on the vertical axis, and the time is plotted on the horizontal axis;

To determine how long it took Henry to run 100m; The point corresponding to 100m is traced downward from the line of the graph and we find out that;

It takes Henry 20seconds to run 100m

b) Henry's average speed over the race is simply;

The slope of the distance-time graph.

Therefore,

  • Average speed = (100-0)/(20-0)

  • Average speed = 100/20

  • Average speed = 5m/s.

Therefore, Henry's average speed over the race is; 5m/s.

Read more:

brainly.com/question/22125199

6 0
2 years ago
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