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Snowcat [4.5K]
3 years ago
6

One of your delivery trucks traveled 1,200 miles on 55 gallons of gas. How many miles per gallon did the truck get? (Round off y

our answer to the nearest hundredth.)
A. 45.84
B. 21.81
C. 45.83
D. 21.82
Physics
2 answers:
Aleksandr-060686 [28]3 years ago
7 0
The word "Per" means divide

"miles per gallon" is the same as "miles / gallon"

The truck went 1,200 miles
on 55 gallons

1,200 ÷ 55 = 21.81
marysya [2.9K]3 years ago
3 0
Simply divide the two quantities to attain the correct unit.

1200 miles/55 gallons = 21.82 miles/gallon
The answer is D.
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Answer:

The compression in the spring is 5.88 meters.                

Explanation:

Given that,

Mass of the car, m = 39000 kg

Height of the car, h = 19 m

Spring constant of the spring, k=4.2\times 10^5\ N/m

We need to find the compression in the spring in stopping the ore car. It can be done by balancing loss in gravitational potential energy and the increase in elastic energy. So,

mgh=\dfrac{1}{2}kx^2

x is the compression in spring

x=\sqrt{\dfrac{2mgh}{k}} \\\\x=\sqrt{\dfrac{2\times 39000\times 19\times 9.8}{4.2\times 10^5}} \\\\x=5.88\ m

So, the compression in the spring is 5.88 meters.                                                                                                                  

6 0
3 years ago
A policeman is chasing a criminal across a rooftop at 10 m/s. He decides to jump to the next building which is 2 meters across f
valina [46]

Answer:

They will meet at a distance of 7.57 m

Given:

Initial velocity of policeman in the x- direction, u_{x} = 10 m/s

The distance between the buildings, d_{x} = 2.0 m

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Solution:

Now,

When the policeman jumps from a height of 2.5 m, then his initial velocity, u was 0.

Thus

From the second eqn of motion, we can write:

h = ut + \frac{1}{2}gt^{2}

h = \frac{1}{2}gt^{2}

2.5 = \frac{1}{2}\times 10\times t^{2}

t = 0.707 s

Now,

When the policeman was chasing across:

d_{x} = u_{x}t + \frac{1}{2}gt^{2}

d_{x} = 10\times 0.707 + \frac{1}{2}\times 10\times 0.5 = 9.57 m

The distance they will meet at:

9.57 - 2.0 = 7.57 m

   

8 0
3 years ago
A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together, wha
g100num [7]
Use conservation of momentum ;

m1u1 + m2u2 = m1v1 + m2v2

1200×15.6 + 0 = 2700v

v = 18720/2700

v = 6.933 or ~ 7 m/s
5 0
3 years ago
HeLp aSAp!!! If the speed and distance of an object are given, and I need to find the time, I will...
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Answer:

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Explanation:

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5 0
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A rock of mass 0.340 kg is spun horizontally at the end of a wire that has a diameter of 1.00 mm. If the wire gets stretched by
borishaifa [10]

Answer:

Y = 78.13 x 10⁹ Pa = 78.13 GPa

Explanation:

First we will find the centripetal force acting on the wire as follows:

F = mv²/r

where,

F = Force = ?

m = mass of rock = 0.34 kg

v = speed = 19 m/s

r = length of wire

Therefore,

F = (0.34)(19)²/r

F = 122.74/r  

now, we find cross-sectional area of wire:

A = πd²/4

where,

A = Area = ?

d = diameter of wire = 1 mm = 0.001 m

Therefore,

A = π(0.001)²/4

A = 7.85 x 10⁻⁷ m²

Now, we calculate the stress on wire:

Stress = F/A

Stress = (122.74/r)/(7.85 x 10⁻⁷)

Stress = 1.56 x 10⁸/r

Now, we calculate strain:

Strain = Δr/r

where,

Δr = stretch in length = 2 mm = 0.002 m

Therefore,

Strain = 0.002/r

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Y = Stress/Strain

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<u>Y = 78.13 x 10⁹ Pa = 78.13 GPa</u>

8 0
2 years ago
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