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Jlenok [28]
3 years ago
12

Please help, thank you

Physics
2 answers:
wlad13 [49]3 years ago
5 0

it might be D but i'm not sure. i hope you find your answer ! :)

IceJOKER [234]3 years ago
5 0
Yeah I’m pretty sure it’s the last one x
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The diagram shows the movement of air as a result of convection currents. At which point is the air at its highest density?
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When you bring two objects of different temperature together, energy will always be transferred from the hotter to the cooler object.  The objects will exchange thermal energy, until thermal equilibrium is reached, i.e. until their temperatures are equal.  We say that heat flows from the hotter to the cooler object.  Heat is energy on the move.  

Units of heat are units of energy.  The SI unit of energy is Joule.  Other often encountered units of energy are 1 Cal = 1 kcal = 4186 J, 1 cal = 4.186 J, 1 Btu = 1054 J.

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6 0
3 years ago
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Speed of 26.7 m/s in 3.06 s. How far had the car traveled by the time the final speed was achieved?
Alik [6]

Answer:

Below

Explanation:

You can use this equation to find the distance :

     distance = velocity x time

     distance = (26.7)(3.06)

                    = 81.702 m

Rounding to 3 sig figs

     = 81.7 m

Hope this helps

6 0
2 years ago
A gun shoots a bullet with a velocity of 500 m/s. The gun is aimed horizontally and fired from a height of 1.5 m. How far does t
MrMuchimi

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity u_x. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,

y=u_yt+\frac{1}{2} gt^2

Substitute 0 m/s for u_y, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.

y=u_yt+\frac{1}{2} gt^2\\ 1.5 m=(0m/s)t+\frac{1}{2} (9.81m/s^2)t^2\\ t=\sqrt{\frac{2(1.5m)}{9.81m/s^2} } =0.5530s

The horizontal distance traveled by the bullet is given by,

x=u_xt

Substitute 500 m/s for u_x and 0.5530s for t.

x=u_xt\\ =(500m/s)(0.5530s)\\ =276.5m

The bullet travels a distance of 276.5 m.


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75 steps is what he’s missing
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An area where the particles in a medium are spaced close together is called compression.

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