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love history [14]
3 years ago
14

Two long, straight wires are parallel and 16 cm apart. One carries a current of 2.9 A, the other a current of 5.7 A. (a) If the

two currents flow in opposite directions, what is the magnitude (in N/m) and direction of the force per unit length of one wire on the other?
Physics
1 answer:
Mnenie [13.5K]3 years ago
5 0

Explanation:

Given that,

Distance between two long wires, d = 16 cm = 0.16 m

Current in one wire, I_1=2.9\ A

Current in wire 2, I_2=5.7\ A    

The magnetic force per unit length of one wire on the other is given by the following expression as :

\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi d}

\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2.9\times 5.7}{2\pi \times 0.16}

\dfrac{F}{l}=2.06\times 10^{-5}\ N/m

The current is flowing in opposite direction, the magnetic force acting on it is repulsive. Hence, this is the required solution.

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2 years ago
Two capacitors of capacitances 25 µF and 50 µF are connected in series with a 33-V battery. How much energy is stored in the 25-
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Answer:

6.05×10⁻³ J

Explanation:

Note: Two capacitors connected in series behaves like two resistors connected in parallel.

Using

1/Ct = 1/C1+1/C2

Ct = (C1×C2)/(C1+C2)............................ Equation 1

Where Ct = combined capacitance of the two capacitor, C1 = Capacitance of the first capacitor, C2 = capacitance of the second capacitor.

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Ct = 16.67 µF.

Using

Q = CV.................... Equation 2

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Q = 33(16.67×10⁻⁶)

Q = 5.5×10⁻⁴ C.

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Using,

E = 1/2Q²/C.................. Equation 3

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Given: Q =5.5×10⁻⁴ C, C = 25 µF = 25×10⁻⁶ F

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E = 6.05×10⁻³ J.

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3 years ago
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