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love history [14]
3 years ago
14

Two long, straight wires are parallel and 16 cm apart. One carries a current of 2.9 A, the other a current of 5.7 A. (a) If the

two currents flow in opposite directions, what is the magnitude (in N/m) and direction of the force per unit length of one wire on the other?
Physics
1 answer:
Mnenie [13.5K]3 years ago
5 0

Explanation:

Given that,

Distance between two long wires, d = 16 cm = 0.16 m

Current in one wire, I_1=2.9\ A

Current in wire 2, I_2=5.7\ A    

The magnetic force per unit length of one wire on the other is given by the following expression as :

\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi d}

\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2.9\times 5.7}{2\pi \times 0.16}

\dfrac{F}{l}=2.06\times 10^{-5}\ N/m

The current is flowing in opposite direction, the magnetic force acting on it is repulsive. Hence, this is the required solution.

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Answer:

A. Archinedes

Explanation:

Archimedes' principle states that a body immersed in a fluid is subjected to an upwards force equal to the weight of the displaced fluid. This is a first condition of equilibrium.

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1 year ago
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One method of determining the location of the center of gravity of a person is to weigh the person as he/she lies on a board of
andrey2020 [161]

Answer:

x = 1.018 m

Explanation:

given,

height of man = 190 cm

                       = 1.9 m

scale reading on left = 450 N

scale reading on the right = 390 N

Let center of gravity of man be x distance from feet, feet is on right side.

For system to be in equilibrium moment about center should be equal to zero.

∑M = 0

now,

450(1.9 - x ) - 390 × x = 0

450(1.9 - x ) = 390 × x

855 - 450 x = 390 x

840 x = 855

 x = \dfrac{855}{840}

 x = 1.018 m

hence, point of center of gravity from feet is equal to x = 1.018 m

7 0
3 years ago
Heat is extracted from a certain quantity of steam at
vodomira [7]

Answer:v=2452.91 m/s

Explanation:

Given

initially steam is at 100^{\circ}C and converted to 0^{\circ} C ice

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latent heat of fusion and vaporization for water is

L_f=3.33\times 10^5 J/kg

L_v=2.26\times 10^6 J/kg

Heat required to convert steam in to water at 100^{\circ}C

Q_1=m\times L_v=m\cdot 2.26\times 10^6 J

Heat required to lower water temperature to 0^{\circ}C

Q_2=m\times c\times \Delta T

Q_2=m\times 4.184\times (100)

Q_2=4.184m\times 10^5 J

Heat required to convert 0^{\circ}C water to ice at 0^{\circ}C is

Q_3=m\times L_f

Q_3=m\times 3.33\times 10^5=3.33m\times 10^5 J

Q=Q_1+Q_2+Q_3

Q=(2.26+0.4184+0.33)m\times 10^6 J

Q=3.0084m\times 10^6 J

So this energy is equal to kinetic energy of  bullet of mass m moving with velocity v

Q=\frac{1}{2}mv^2

3.0084m\times 10^6=\frac{1}{2}mv^2

v^2=3.0084\times 2\times 10^6

v=2.452\times 10^3 m/s

v=2452.91 m/s  

5 0
3 years ago
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. The initial temperature of the gas is 28.0
mel-nik [20]

Answer:

63.5 °C

Explanation:

The expression for the calculation of work done is shown below as:

w=P\times \Delta V

Where, P is the pressure

\Delta V is the change in volume

Also,

Considering the ideal gas equation as:-

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 8.314 J/ K mol

So,

V=\frac{nRT}{P}

Also, for change in volume at constant pressure, the above equation can be written as;-

\Delta V=\frac{nR\times \Delta T}{P}

So, putting in the expression of the work done, we get that:-

w=P\times \frac{nR\times \Delta T}{P}=nR\times \Delta T

Given, initial temperature = 28.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (28.0 + 273.15) K = 301.15 K

W=1770 J

n = 6 moles

So,

1770\ J=6 moles\times 8.314\ J/ Kmol \times (T_2-301.15\ K)

Thus,

T_2=301.15\ K+\frac{1770}{6\times 8.314}\ K

T_2=336.63\ K

The temperature in Celsius = 336.63-273.15 °C = 63.5 °C

<u>The final temperature is:- 63.5 °C</u>

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