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2 years ago

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Water is falling on the blades of a turbine at a rate of 100 kg/s from a certain spring. If the height of spring be 100m, then t

he power transferred to the turbine will be: a) 100 KW b) 10 KW c) 1 KW d) 100 W

1 answer:

pashok25 [27]2 years ago

4 0

Answer:

Natae Si Jordan Kaya Sya Napaihe

Explanation:

haha

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A gas is compressed at a constant pressure of 0.800 atm from 12.00 L to 3.00 L. In the process, 390 J of energy leaves the gas b

Andru [333]

Answer:

a)W= - 720 J

b)ΔU= 330 J

Explanation:

Given that

P = 0.8 atm

We know that 1 atm = 100 KPa

P = 80 KPa

V₁ = 12 L = 0.012 m³ ( 1000 L = 1 m³)

V₂ = 3 L = 0.003 m³

Q= - 390 J ( heat is leaving from the system )

We know that work done by gas given as

W = P (V₂ -V₁ )

W= 80 x ( 0.003 - 0.012 ) KJ

W= - 0.72 KJ

W= - 720 J ( Negative sign indicates work done on the gas)

From first law of thermodynamics

Q = W + ΔU

ΔU=Change in the internal energy

Now by putting the values

- 390 = - 720 + ΔU

ΔU= 720 - 390 J

ΔU= 330 J

5 0

3 years ago

The average diameter of one tennis ball in a package of three is 6.8 cm. Which of the following is the combined volume of all th

Crank

We want to find the combined volume of 3 tennis balls. We will get that the combined volume is 493.7 cm^3

First, remember that for a sphere of diameter D, the volume is:

$V = \frac{4}{3}*3.14*(\frac{D}{2})^3$

Where 3.14 is pi.

Here we know that the average diameter of a tennis ball is 6.8cm, then we can replace that in the above equation to find the volume (in average) of a single tennis ball:

$V = \frac{4}{3}*3.14*(\frac{6.8cm}{2})^3 = 164.5 cm^3$

Now, in 3 balls of tennis, the combined volume will be 3 times the above one, this is:

$3*V = 3*164.5cm^3 = 493.7 cm^3$

If you want to learn more about volumes, you can read:

brainly.com/question/10171109

4 0

2 years ago

An ideal transformer has 60 turns in its primary coil and 360 turns in its secondary coil. If the input rms voltage for the 60-t

notka56 [123]

Answer:

720 V

Explanation:

Given that,

The number of turns in primary coil, N₁ = 60

The number of turns in secondary coil, N₂ = 360

The input rms voltage, V₁ = 120 V

We need to find the output rms voltage of the secondary coil . The relation between number of turns in primary coil - secondary coil to the input rms voltage to the output rms voltage is given by :

$\dfrac{N_1}{N_2}=\dfrac{V_1}{V_2}\\\\V_2=\dfrac{N_2V_1}{N_2}\\\\V_2=\dfrac{360\times 120}{60}\\\\V_2=720\ V$

<h3>So, the output rms voltage of the secondary coil is 720 V. Hence, the correct option is (b).</h3>

7 0

2 years ago

When the temperature of water increases from room temperature to 90*C the process of heating the water is

polet [3.4K]

The process is called ENDOTHERMIC

8 0

3 years ago

What volume of lead must be fastened underneath it to sink the wood in calm water so that its top is just even with the water le

astraxan [27]

The bouyancy force is:

Since the wood-lead system is completely submerged, the bouyancy force

is FB = ĎwgVl + ĎwgVb, where Ďw is the density of water,Vl

is the volume of

the piece of lead and Vb is the volume of the wooden block. The weight of the

  combined lead and wooden block is: W = ĎlgVl + ĎbgVb. Since the system is

in equilibrium, the bouyancy force must be equal to the total weight:

ĎwgVl + ĎwgVb = ĎlgVl + ĎbgVb

now we can solve for the volume of lead:

ĎwgVl â’ ĎlgVl = ĎbgVb â’ ĎwgVb

Vl(Ďw â’ Ďl) = Vb(Ďb â’ Ďw)

Vl =

Ďbâ’Ďw

Ďwâ’Ďl

Vb

Now we substitute the values for the density of lead Ďl = 11.3 Ă— 103kg/m3  ,

the density of the wood and the density of water Ďw = 1000kg/m3

. We get:

Vl =

600â’1000

1000â’11300

(0.6m Ă— 0.25m Ă— 0.08m) = 4.66 Ă— 10â’4m3

4 0

3 years ago