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2 years ago

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Water is falling on the blades of a turbine at a rate of 100 kg/s from a certain spring. If the height of spring be 100m, then t

he power transferred to the turbine will be: a) 100 KW b) 10 KW c) 1 KW d) 100 W

1 answer:

pashok25 [27]2 years ago

4 0

Answer:

Natae Si Jordan Kaya Sya Napaihe

Explanation:

haha

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Photovoltaic cells: a) have become more economical to produce and use over the past 25 years. b) are the most efficient means of

Yanka [14]

Photovoltaic cells are the most efficient means of converting solar energy to electricity. Option b is correct.

<h3>What is a cell?</h3>

A cell is a voltage and current-producing device that consists of a single anode and cathode separated by an electrolyte.

One or more cells can make up a battery. One cell, for example, is one AA battery.

Light intensity on a solar cell is often measured in "suns," with one sun roughly equivalent to 1 kW/m².

Concentrated sunlight improves the ratio of current generated while the device is lighted vs when it is dark, hence enhancing output voltage and efficiency.

Photovoltaic cells are the most efficient means of converting solar energy to electricity.

Hence, option b is correct.

To learn more about the cell refer to:

brainly.com/question/3142913

#SPJ1

8 0

1 year ago

A silver wire with resistivity 1.59 × 10-8 Ω-m carries a current density of 4.0 A/mm2, What is the magnitude of the electric fie

Nat2105 [25]

Answer:

Electric field, E = 0.064 V/m

Explanation:

It is given that,

Resistivity of silver wire, $\rho=1.59\times 10^{-8}\ \Omega-m$

Current density of the wire, $J=4\ A/mm^2=4\times 10^6\ A/m^2$

We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :

$E=J\times \rho$

$E=4\times 10^6\times 1.59\times 10^{-8}$

E = 0.0636 V/m

or

E = 0.064 V/m

So, the magnitude of electric field inside the wire is 0.064 V/m. Hence, this is the required solution.

6 0

2 years ago

Consider this situation: A baseball player dives head-first

siniylev [52]

Of the forces listed I think the force of him diving and sliding across the infield acted on the player.

I think so because the slowing down was a result of an action, and I don’t think that should count as An action when it is the result of an action. However, the act of diving head-first into second base and sliding across the infield are independent actions and will cause friction, which will act upon the player.

7 0

2 years ago

Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t

wolverine [178]

Answer:

final velocity = 0.08585m/s

Explanation:

We are taking train cars as our system. In this system no external force is acting. So we can apply the law of conservation of linear momentum.

The law of conservation of linear momentum states that the total linear momentum of a system remains constant if there is no external force acting on the system. That is total linear momentum before = total linear momentum after

total linear momentum before = linear momentum of first train car + linear momentum of second train car

We know that linear momentum = mv

where,

m = mass

v = velocity

thus,

total linear momentum before = m₁v₁ + m₂v₂

m₁ = mass of first train car = 135,000kg

v₁ = velocity of first train car = 0.305m/s

m₂ = mass of first second car = 100,000kg

v₂ = velocity of second train car = −0.210m/s

Note: Momentum is a vector. So while adding momentum we should take account of its direction too. Here since second train car is moving in a direction opposite to that of the first one, we have taken its velocity as negative.

total linear momentum before = m₁v₁ + m₂v₂

= 135,000x0.305 + 100,000x(−0.210)

= 135,000x0.305 - 100,000x0.210

= 20,175 kgm/s

Now we have to find total linear momentum after bumping. After the bumping both the train cars will be moving together with a common velocity(say v).

Therefore, total linear momentum after = mv

m = m₁ + m₂ = 135,000 + 100,000 = 235,000

total linear momentum before = total linear momentum after

235,000v = 20,175

v = $\frac{20,175}{235,000}$

= 0.08585m/s

8 0

2 years ago

Read 2 more answers

A spring has a spring constant of 80 N/m. How much energy is stored in the spring when it is compressed 0.2 m past its natural l

Paha777 [63]

The energy of a compressed (or stretched) spring is given by

$E= \frac{1}{2} k x^{2}$

This gives

$E= \frac{1}{2}80* 0.2^{2} =1.6J$

5 0

3 years ago