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Dmitry_Shevchenko [17]
3 years ago
5

What happens when the cell of a unicellular organism divides? Text to speech A:A. The unicellular organism dies. B:B. The unicel

lular organism grows larger. C:C. The unicellular organism creates a new organism. D:D. The unicellular organism becomes a multicellular organism.
Chemistry
1 answer:
murzikaleks [220]3 years ago
7 0

Answer: Option C) The unicellular organism creates a new organism.

Explanation:

Cell division involves the multiplication of cells whereby one cell divides into two daughter cells or offsprings, two divides into four and so on.

In unicellular organisms, cell division could be by the following ways:

- Binary fission in Ameoba

- Budding in Hydra

- fragmentation in Sponges.

Thus, each of these unicellular organisms divides to give rise to new organisms that are similar to their parents

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3 the h2o molecule itself is small in size
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What is the average rate of formation of i2? express your answer to three decimal places and include the appropriate units. view
Klio2033 [76]
Missing question:
Chemical reaction: H₂ <span>+ 2ICl → 2HCl + I</span>₂.
t₁ = 5 s.
t₂ = 15 s.
c₁ = 1,11 M = 1,11 mol/L.
c₂ = 1,83 mol/L.
rate of formation = Δc ÷ Δt.
rate of formation = (c₂ - c₁) ÷ (t₂ - t₁).
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3 years ago
The earths magnetic poles are located in different areas close to its geographic poles?
s2008m [1.1K]

Answer:

Explanation:

The answer is true

4 0
2 years ago
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Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2N
Montano1993 [528]

The question is incomplete, here is the complete question:

Urea (CH₄N₂O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH₃) with carbon dioxide as follows: 2NH₃(aq) + CO₂(aq) → CH₄N₂O(aq) + H₂O(l) In an industrial synthesis of urea, a chemist combines 135.9 kg of ammonia with 211.4 kg of carbon dioxide and obtains 178.0 kg of urea.

Determine the limiting reactant. (express your answer as a chemical formula)

<u>Answer:</u> The limiting reactant is ammonia (NH_3)

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For ammonia:</u>

Given mass of ammonia = 135.9 kg = 135900 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonia}=\frac{135900g}{17g/mol}=7994.12mol

  • <u>For carbon dioxide gas:</u>

Given mass of carbon dioxide gas = 211.4 kg = 211400 g

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon dioxide gas}=\frac{211400g}{44g/mol}=4804.54mol

The given chemical reaction follows:

2NH_3(aq.)+CO_2(aq,)\rightarrow CH_4N_2O(aq.)+H_2O(l)

By Stoichiometry of the reaction:

2 moles of ammonia reacts with 1 mole of carbon dioxide

So, 7994.12 moles of ammonia will react with = \frac{1}{2}\times 7994.12=3997.06mol of carbon dioxide

As, given amount of carbon dioxide is more than the required amount. So, it is considered as an excess reagent.

Thus, ammonia is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reactant is ammonia (NH_3)

5 0
3 years ago
(WILL GIVE BRAINLESS)Throwing a paper airplane through the air is an example of A. fluid friction B. sliding friction C. rolling
Scilla [17]

Answer:

sliding friction

Explanation:

8 0
3 years ago
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