The math is set up like
35.6 ml * 2.7 g/ 1 ml
which will leave you with
96.12 g
I think it's reactivity. but i'm not sure.
The volume of 0.160 m Li2S solution required to completely react with 130 ml of 0.160 CO(NO3)2 is calculated as below
write the reacting equation
Co(NO3)2 + Li2S = 2LiNO3 + COS
find the moles of CO(NO3)2 = molarity x volume
= 130 ml x 0.160=20.8 moles
since the reacting moles between CO(NO3)2 to LiS is 1:1 the moles of LiS is also 20.8 moles
volume of Lis is therefore = moles of Lis/ molarity of LiS
= 20.8/0.160 = 130 Ml
Answer: There are 
molecules 
gas are in 756.2 L.
Explanation:
It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of moles present in 756.2 L are calculated as follows.
According to mole concept, 1 mole of every substance contains 
molecules.
Therefore, molecules of S present in 33.76 moles are calculated as follows.
Thus, we can conclude that there are molecules gas are in 756.2 L.
