According to Law of conservation of matter," matter can neither be created nor destroyed but is conserved and remains constant over time'.
In above picture let suppose the Blue balls represent N₂ molecule and White balls represent H₂ molecules.
So, left picture represent reactants,
2 N₂ + 6 H₂
And , right picture represent products,
4 NH₃
So, there are 4 N atoms and 12 Hydrogen atoms in reactants and 4 N atom and 12 Hydrogen atoms in products. Means the mass of elements is conserved. The overall reactions is as follow,
2 N₂ + 6 H₂ → 4 NH₃
Result: Yes! This reaction follow Law of conservation of Matter.
The combined gas law states that the pressure of a gas is inversely related to the volume and directly related to the temperature. If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase.
- rusting - change in base of chemical - for example lets say u mix two chemicals, and then it becomes a different new chemical (it changed from the inside)
a physical
- a physical reaction is outer looks not inside. - it changes on the outside, like changing a color
Explanation: In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for pressure and temperature. Since no mention of those conditions was made, I'll assume that the reaction takes place at STP, Standard Temperature and Pressure. STP conditions are defined as a pressure of 100 kPa and a temperature of 0 ∘ C . Under these conditions for pressure and temperature, one mole of any ideal gas occupies 22.7 L - this is known as the molar volume of a gas at STP. So, in order to find the volume of oxygen gas at STP, you need to know how many moles of oxygen are produced by this reaction. The balanced chemical equation for this decomposition reaction looks like this 2 KClO 3(s] heat × −−−→ 2 KCl (s] + 3 O 2(g] ↑ ⏐ ⏐ Notice that you have a 2 : 3 mole ratio between potassium chlorate and oxygen gas. This tells you that the reaction will always produce 3 2 times more moles of oxygen gas than the number of moles of potassium chlorate that underwent decomposition. Use potassium chlorate's molar mass to determine how many moles you have in that 231-g sample 231 g ⋅ 1 mole KClO 3 122.55 g = 1.885 moles KClO 3 Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate 1.885 moles KClO 3 ⋅ 3 moles O 2 2 moles KClO 3 = 2.8275 moles O 2 So, what volume would this many moles occupy at STP? 2.8275 moles ⋅ 22.7 L 1 mol = 64.2 L
