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givi [52]
3 years ago
12

Two positions of the sun, moon, and Earth are described below: Position A: Moon is between the sun and Earth Position B: Moon an

d sun are at right angles to each other relative to Earth
Which statement is true regarding the type of tides that can occur?

A neap tide can occur for both positions A and position B.

A spring tide can occur for both positions A and position B.

A neap tide can occur for position A but not for position B.

A spring tide can occur for position A but not for position B.
Physics
2 answers:
choli [55]3 years ago
6 0
The third statement is true:
A neap tide can occur for position A but not position B

Position B is a Spring tide
Harman [31]3 years ago
5 0
<span>Position A: Moon is between the sun and Earth
Position B: Moon and sun are at right angles to each other relative to Earth 

</span><span>A spring tide can occur for position A but not for position B.</span>
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Calculate the kinetic energy in joules of a 1500 kg automobile moving at 17 m/s . express your answer to two significant figures
Sidana [21]
Kinetic energy = 1/2 (mass)*(velocity)^2

ke = 1/2 (1500kg) (17m/s)^2
ke = 216750 kg*m^2/s^2 = 216750 Joules

(sorry, I don't know significant figures. but this is otherwise the correct answer with the right units. hope this helps!! :))
6 0
4 years ago
What is the energy stored between 2 Carbon nuclei that are 1.00 nm apart from each other? HINT: Carbon nuclei have 6 protons and
Andrei [34K]

Answer:

A. 8.29\times 10^{-18}\ J

Explanation:

Given that:

p = magnitude of charge on a proton = 1.6\times 10^{-19}\ C

k = Boltzmann constant = 9\times 10^{9}\ Nm^2/C^2

r = distance between the two carbon nuclei = 1.00 nm = 1.00\times 10^{-9}\ m

Since a carbon nucleus contains 6 protons.

So, charge on a carbon nucleus is q = 6p=6\times 1.6\times 10^{-19}\ C=9.6\times 10^{-19}\ C

We know that the electric potential energy between two charges q and Q separated by a distance r is given by:

U = \dfrac{kQq}{r}

So, the potential energy between the two nuclei of carbon is as below:

U= \dfrac{kqq}{r}\\\Rightarrow U = \dfrac{kq^2}{r}\\\Rightarrow U = \dfrac{9\times10^9\times (9.6\times 10^{-19})^2}{1.0\times 10^{-9}}\\\Rightarrow U =8.29\times 10^{-18}\ J

Hence, the energy stored between two nuclei of carbon is 8.29\times 10^{-18}\ J.

8 0
3 years ago
The plane is flying with a velocity of 220m/s when it encounters a 45 m/s wind blowing same direction as the planes motion calul
Inga [223]

Answer:

I have no idea

Explanation:

5 0
3 years ago
A particle of charge of +3.40 ✕ 10−6 C is 17.5 cm distant from a second particle of charge of −2.00 ✕ 10−6 C. Calculate the magn
Karolina [17]

Answer:

0.47 N

Explanation:

q1 = 3.4 x 10^-6 C

q2 = 2 x 10^-6 C

d = 17.5 cm = 0.175 m

The electrostatic force is given by

F=\frac{Kq_{1}q_{2}}{d^{2}}

F=\frac{9\times10^{9}\times3.4\times 10^{-6}\times 2\times 10^{-6}}{0.175\times 0.175}

F = 0.47 N

Thus, the force is 0.47 N.

5 0
3 years ago
A static electric charge can be released as __________. *
poizon [28]
A, a spark because if you touch something after rubbing your hand on carpet or something you get a spark
8 0
3 years ago
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